看来,用于将视图呈现为字符串的大多数代码在MVC 5中都不起作用。
我有最新的MVC 5.1.2模板,我正在尝试将视图呈现为字符串。
public static String RenderViewToString(ControllerContext context, String viewPath, object model = null)
{
context.Controller.ViewData.Model = model;
using (var sw = new StringWriter())
{
var viewResult = ViewEngines.Engines.FindView(context, viewPath, null);
var viewContext = new ViewContext(context, viewResult.View, context.Controller.ViewData, context.Controller.TempData, sw);
viewResult.View.Render(viewContext, sw);
viewResult.ViewEngine.ReleaseView(context, viewResult.View);
return sw.GetStringBuilder().ToString();
}
}
嗯,它正在运行,但它的输出包含许多$标记而不是标记。我读过一些关于它的内容已在RC版本中修复,但那是旧闻。
问题看起来像这样
<$A$><h1></h1>
<table</$A$><$B$> class=""</$B$><$C$>> <tbody</$C$><$D$></$D$><$E$>></tbody>
</table></$E$>
我想问一下,如何在最新的MVC 5模板中将视图呈现为字符串? 感谢。
答案 0 :(得分:29)
好的,我似乎找到了解决方案。这个想法的作者是亚基尔庄园。
class FakeController : ControllerBase
{
protected override void ExecuteCore() { }
public static string RenderViewToString(string controllerName, string viewName, object viewData)
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
var razorViewEngine = new RazorViewEngine();
var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
}
这是假上下文和响应的技巧。
示例:
String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );
我的文件MyHTMLView.cstml存储在Views / Email / MyHTMLView.cshtml中。电子邮件是一个虚假的控制器名称。
答案 1 :(得分:5)
以下是适用于MVC5上的会话和区域的解决方案。
public class FakeController : ControllerBase
{
protected override void ExecuteCore() { }
public static string RenderViewToString(string controllerName, string viewName,string areaName, object viewData,RequestContext rctx)
{
try
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
routeData.Values.Add("Area", areaName);
routeData.DataTokens["area"] = areaName;
var fakeControllerContext = new ControllerContext(rctx, new FakeController());
//new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
fakeControllerContext.RouteData = routeData;
var razorViewEngine = new RazorViewEngine();
var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.GetStringBuilder().ToString();
//use example
//String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );
//where file MyHTMLView.cstml is stored in Views/Email/MyHTMLView.cshtml. Email is a fake controller name.
}
}
catch (Exception ex)
{
//do your exception handling here
}
}
}
这是你如何从另一个控制器调用它
var modal = getModal(params);
return FakeController.RenderViewToString(controllerName, viewName, areaName, modal, this.Request.RequestContext);
使用requestcontext我们可以轻松地在fakecontroller中传递当前会话并呈现razor字符串。
答案 2 :(得分:2)
我迫切需要在JSON对象中将6个部分视图作为字符串返回。我决定将受保护的方法添加到源自Controller的ControllerBase类,而不是创建静态方法并传递所有不需要的参数,并将其用作所有控制器的基类。
这是一个功能齐全的ControllerBase类,它提供此功能,其工作方式与Controller类中的PartialView()和View()方法非常相似。它包括@Alok的补充。
public abstract class ControllerBase : Controller
{
#region PartialViewToString
protected string PartialViewToString(string partialViewName, object model = null)
{
ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindPartialView(controllerContext, partialViewName) ?? throw new FileNotFoundException("Partial view cannot be found."),
model
);
}
#endregion
#region ViewToString
protected string ViewToString(string viewName, object model = null)
{
ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
model
);
}
protected string ViewToString(string viewName, string controllerName, string areaName, object model = null)
{
RouteData routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
if (areaName != null)
{
routeData.Values.Add("Area", areaName);
routeData.DataTokens["area"] = areaName;
}
ControllerContext controllerContext = new ControllerContext(HttpContext, routeData, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
model
);
}
#endregion
#region Private Methods
private string ViewToString(ControllerContext controllerContext, ViewEngineResult viewEngineResult, object model)
{
using (StringWriter writer = new StringWriter())
{
ViewContext viewContext = new ViewContext(
ControllerContext,
viewEngineResult.View,
new ViewDataDictionary(model),
new TempDataDictionary(),
writer
);
viewEngineResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
#endregion
}
答案 3 :(得分:0)
@ wh1sp3r答案有效,但对于部分视图,我必须进行以下较小更改:
string html = FakeController.RenderViewToString("**Controllername**", "~/views/**Controllername**/_AsdfPartialPage.cshtml", fem);
public static string RenderViewToString(string controllerName, string viewName, object viewData)
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://localhost", null), new HttpResponse(null))), routeData, new FakeController());
var razorViewEngine = new RazorViewEngine();
//var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var razorViewResult = razorViewEngine.FindPartialView(fakeControllerContext, viewName, false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
答案 4 :(得分:0)
要将PartialView呈现为字符串,请使用以下代码:
class FakeController: ControllerBase {
protected override void ExecuteCore() { }
public static string RenderViewToString(string controllerName, string viewName, object model) {
using(var writer = new StringWriter()) {
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://localhost", null), new HttpResponse(null))), routeData, new FakeController());
var razorViewEngine = new RazorViewEngine();
var razorViewResult = razorViewEngine.FindPartialView(fakeControllerContext, viewName, false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(model), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
}