Question

我想从我的数据中选择不同的记录，此时它会显示重复的记录。以下是我的查询的外观：

SELECT DISTINCT ID,
  FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee

我已经包含了不同的词，但我仍然得到重复的结果

Answer 1

DISTINCT关键字与该列一起使用，您想要获得不同的值，ID始终是不同的。作为DISTINCT FirstName比名字将是不同的。

Answer 2

您要么寻找：

SELECT FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee

OR

SELECT ID,
  FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee,
  COUNT(
  CASE TotalAwards
    WHERE 1
    THEN 1
    ELSE NULL
  END),
  COUNT(
  CASE TotalRespect
    WHERE 1
    THEN 1
    ELSE NULL
  END)
FROM tablename
GROUP BY ID, 
FirstName,
  SecondName,
  Department,
  Company,
  TotalEmployee

Answer 3

你可以使用row_number（）和partition by（）来获得所需的结果

尝试这样：

select * from
(
select *,rn=row_number()over(partition by Totalawards,totalrespect order by Firstname)
from table
)x
where x.rn=1

如何选择不同的记录

3 个答案: