Question

我有一个这样的原生选择：

 occupationSelect = new NativeSelect("Occupation:");
    occupationSelect.setRequired(true);
    occupationSelect.setRequiredError("Must Not be Empty");
    occupationSelect.setImmediate(true);
    occupationSelect.setWidth(COMMON_FIELD_WIDTH);
    occupationSelect.setNullSelectionItemId(0);
    occupationSelect.setItemCaption(0, "--Select");
    occupationSelect.addItem(1);
    occupationSelect.setItemCaption(1, "static");

在模态类Registration.java

中

    private OccupationBean occupationBean;

OccupationBean.java

    private Long occupationId;
    private String occupationName;

绑定此字段

  binderFieldGroupPersonalDetails.bind(occupationSelect,
            "occupationBean.occupationId");

我收到此错误：

无法将java.lang.Integer类型的值转换为模型类型类java.lang.Long。没有设置转换器且类型不兼容。

没有IntegerToLong的默认转换器

我该如何实现这个

Answer 1

只需使用0L而不是0

occupationSelect.setNullSelectionItemId(0L);
occupationSelect.setItemCaption(0L, "--Select");
occupationSelect.addItem(1L);
occupationSelect.setItemCaption(1L, "static");

如何转换nativeselect选择值vaadin

1 个答案: