所以,我尝试过很多东西,但没有用这个
建立一个解决方法我有这个代码在Chrome上运行正常。但它确实不适用于Mozilla或IE,在控制台中它不会显示任何错误。它只是没有用。
<?php
echo"<script>alert('okay');</script>";
?>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta charset="UTF-8" />
</head>
<script type="text/javascript" LANGUAGE="JavaScript1.3">
function name3() {
var abc = document.createElement("FORM");
//abc.setAttribute("method","POST");
abc.method = "POST";
abc.action = "http://localhost/2.php";
var a = document.createElement("INPUT");
/*a.setAttribute("type","text");
a.setAttribute("name","a");
a.setAttribute("value","abc");*/
a.name = 'a';
a.value = "abc";
abc.appendChild(a);
abc.submit();
}
</script>
<input type = "button" onclick = "name3();" value = "click">
</html>
而不是a.name,我也尝试过使用a.setAttribute但仍然没有工作
请帮忙!!!谢谢:))
答案 0 :(得分:0)
您应该将表格附加到正文,然后在发布后将其删除。目前您没有将表单添加到DOM。它实际上需要在DOM中以页面加载的方式发送。
完整代码
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta charset="UTF-8" />
<script type="text/javascript">
function name3() {
var form = document.createElement("FORM");
form.method = "POST";
form.action = "http://localhost/2.php";
var a = document.createElement("INPUT");
a.name = 'a';
a.value = "abc";
form.appendChild(a);
//Apend form to body
document.getElementsByTagName('body')[0].appendChild(form);
//Submit form
form.submit();
// But once the form is sent, it's useless to keep it.
document.getElementsByTagName('body')[0].removeChild(form);
}
</script>
</head>
<body>
<input type="button" onclick="name3();" value="click" />
</body>
</html>
答案 1 :(得分:0)
您应首先将新元素添加到DOM树,然后提交表单。如果您不想显示它们,可以添加样式来隐藏元素。
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta charset="UTF-8" />
</head>
<script type="text/javascript">
function name3() {
var abc = document.createElement("FORM");
//abc.setAttribute("method","POST");
abc.method = "POST";
abc.action = "http://localhost/2.php";
var a = document.createElement("INPUT");
/*a.setAttribute("type","text");
a.setAttribute("name","a");
a.setAttribute("value","abc");*/
a.name = 'a';
a.value = "abc";
abc.appendChild(a);
document.getElementById("body").appendChild(abc);
abc.submit();
}
</script>
<body id="body">
<input type = "button" onclick = "name3();" value = "click">
</body>