Question

我正在运行SSMS 2008

select 
    A.JOBNUMBR as [Service Call], A.PONUMBER as [PO Number], 
    sum(A.QTYUNCMTBASE*A.UNITCOST) as [Committed Cost PO], 
    SUM(B.WS_Committed_Cost) as [Committed Cost WS], 
    (sum(A.QTYUNCMTBASE*A.UNITCOST)-SUM(B.WS_Committed_Cost)) as [Variance]
from 
    POP10110 A
LEFT JOIN 
    SV_Costs B on A.JOBNUMBR = B.Service_Call_ID and A.PONUMBER = B.Reference_TRX_Number and B.WS_Committed_Cost <> 0
where 
    A.Product_Indicator = 3
    and A.QTYUNCMTBASE <> 0
    and (sum(A.QTYUNCMTBASE * A.UNITCOST) - SUM(B.WS_Committed_Cost)) <> 0
group by 
    A.JOBNUMBR, A.PONUMBER
order by 
    A.JOBNUMBR, A.PONUMBER

运行此查询时，我在主题行中收到错误MSG 147。第3个where子句与我试图过滤到＆lt;＆gt;的聚合列[Variance]相同0.查询在没有第3个where子句的情况下运行。

我一直在做一些阅读并理解我需要在where子句中包含HAVING或select语句，但我不能正确地理解语法，任何帮助都会受到赞赏。

谢谢

塔尼亚

Answer 1

Sum是一个聚合列，在您的选择（WHERE子句）中使用无效。一种解决方案是将其包装在另一个SELECT上。 OR：

SELECT
          A.JOBNUMBR as [Service Call], 
          A.PONUMBER as [PO Number], 
          SUM(A.QTYUNCMTBASE*A.UNITCOST) as [Committed Cost PO], 
          SUM(B.WS_Committed_Cost) as [Committed Cost WS], 
          SUM(A.QTYUNCMTBASE*A.UNITCOST) - SUM(B.WS_Committed_Cost) as [Variance]
FROM      POP10110 A
LEFT JOIN SV_Costs B 
       ON A.JOBNUMBR = B.Service_Call_ID 
          AND A.PONUMBER = B.Reference_TRX_Number 
          AND B.WS_Committed_Cost <> 0
WHERE     A.Product_Indicator = 3
      AND A.QTYUNCMTBASE <> 0
GROUP BY  A.JOBNUMBR, A.PONUMBER 
   HAVING (SUM(A.QTYUNCMTBASE * A.UNITCOST) - SUM(B.WS_Committed_Cost)) <> 0
ORDER BY  A.JOBNUMBR, A.PONUMBER

消息147聚合可能不会出现在WHERE子句中，除非它位于HAVING子句或选择列表中包含的子查询中

1 个答案: