import sys
import pickle
import string
def Menu():
print ("***********MENU************")
print ("0. Quit")
print ("1. Read text file")
print ("2. Display counts")
print ("3. Display statistics of word lengths")
print ("4. Print statistics to file")
def readFile():
while True:
fileName = input("Please enter a file name: ")
if (fileName.lower().endswith(".txt")):
break
else:
print("That was an incorrect file name. Please try again.")
continue
return fileName
THE_FILE = ""
myDictionary = 0
def showCounts(fileName):
numCount = 0
dotCount = 0
commaCount = 0
lineCount = 0
wordCount = 0
with open(fileName, 'r') as f:
for line in f:
wordCount+=len(line.split())
lineCount+=1
for char in line:
if char.isdigit() == True:
numCount+=1
elif char == '.':
dotCount+=1
elif char == ',':
commaCount+=1
print("Number count: " + str(numCount))
print("Comma count: " + str(commaCount))
print("Dot count: " + str(dotCount))
print("Line count: " + str(lineCount))
print("Word count: " + str(wordCount))
def showStats(fileName):
temp1 = []
temp2 = []
lengths = []
myWords = []
keys = []
values = []
count = 0
with open(fileName, 'r') as f:
for line in f:
words = line.split()
for word in words:
temp2.append(word)
temp1.append(len(word))
for x in temp1:
if x not in lengths:
lengths.append(x)
lengths.sort()
dictionaryStats = {}
for x in lengths:
dictionaryStats[x] = []
for x in lengths:
for word in temp2:
if len(word) == x:
dictionaryStats[x].append(word)
for key in dictionaryStats:
print("Key = " + str(key) + " Total number of words with " + str(key) + " characters = " + str(len(dictionaryStats[key])))
return dictionaryStats
def printStats(aDictionary):
aFile = open("statsWords.dat", 'w')
for key in aDictionary:
aFile.write(str(key) + " : " + str(aDictionary[key]) + "\n")
aFile.close()
choice = -1
while choice !=0:
Menu()
choice = (int(input("Please choose 1-4 to perform function. Press 0 to exit the program. Thank you. \n")))
if choice == 0:
print ("Exit program. Thank you.")
sys.exit
elif choice == 1:
THE_FILE = readFile()
elif choice == 2:
showCounts(THE_FILE)
elif choice == 3:
showStats(THE_FILE)
elif choice == 4:
printStats(myDictionary)
else:
print ("Error.")
我正在尝试打开一个文件,让它显示字长的统计信息,然后让它创建一个带有字长统计信息的新文件。我可以读取文件并让它显示统计信息,但是当我将统计信息打印到文件时,我得到一个错误 - “int”对象不可迭代。有任何想法吗?谢谢你们!
Error:
Traceback (most recent call last):
File "hw4_ThomasConnor.py", line 111, in <module>
printStats(myDictionary)
File "hw4_ThomasConnor.py", line 92, in printStats
for key in aDictionary:
TypeError: 'int' object is not iterable
答案 0 :(得分:1)
问题是您将myDictionary
设置为程序顶部的0
,然后将其发送到您的文件写入功能printStats(myDictionary)
。
在此功能中,您有for key in aDictionary
这一行,并且在您传入0
后,这实际上是for key in 0
,这是错误的来源。
您需要将showStats
功能的结果发送到printStats
功能。
由于这看起来像是家庭作业,我现在就把它留在那里。
抱歉,我很困惑。在showStats函数我不得不以某种方式说 &#34;将结果发送到printStats函数&#34;然后在printStats中 功能我要调用结果?我该怎么做呢?
printStats函数需要打印字典。这个字典是由showStats函数生成的(事实上,它返回这个字典)。
所以你需要将showStats函数的结果发送到printStats函数。
要保存方法的返回值,可以在调用表达式的LHS(左侧)上分配它,如下所示:
>>> def foo(bar):
... return bar*2
...
>>> def print_results(result):
... print('The result was: {}'.format(result))
...
>>> result = foo(2) # Save the returned value
由于result
与Python中的任何其他名称一样,您可以将其传递给任何其他函数:
>>> print_results(result)
The result was: 4
如果我们不想存储函数的结果,只想将其发送到另一个函数,那么我们可以使用以下语法:
>>> print_results(foo(2))
The result was: 4
您需要在执行函数的主循环中执行类似的操作。
由于showStats函数返回了要打印的字典,因此必须先调用showStats函数,然后再调用printStats函数。如果您的用户在选择3之前选择4,则会出现问题 - 请确保找到解决方法。一个简单的解决方法是在选择之前通过选择3来提示用户计算统计数据。试着想出另一种方法来解决这个问题。
答案 1 :(得分:0)
下面:
THE_FILE = ""
myDictionary = 0
您将整数设置为myDictionary
。
以后再做:
printStats(myDictionary)
当你尝试在里面对词典的键进行交互时,你会失败。