Question

我在网上搜索过，但我找不到任何满意的答案。从字符串重构Javascript Date对象的正确方法是什么，该字符串是使用Date编码的另一个$.param()对象的表示。请注意，我只能访问序列化的日期字符串。它正在查询字符串中传入。我需要重建一个Date。我是Javascript的新手，所以，如果我遗漏任何非常基本的东西，请好好告诉我。

        var dtObj = { startTime: new Date() };
        var paramDtObj = $.param(dtObj);
        console.log(paramDtObj);//startTime=Mon+May+05+2014+12%3A33%3A09+GMT-0700+(Pacific+Daylight+Time)

        var serDtString = "Mon+May+05+2014+12%3A33%3A09+GMT-0700+(Pacific+Daylight+Time)";

        var reconstructedDt1 = new Date(serDtString);
        console.log(reconstructedDt1);//Invalid Date 

        var reconstructedDt2 = new Date(decodeURIComponent(serDtString));
        console.log(reconstructedDt2);//Invalid Date 

        var reconstructedDt3 = new Date(decodeURIComponent(serDtString).replace(/\+/g, " "));
        console.log(reconstructedDt3);//WORKS. Output is - Mon May 05 2014 12:33:09 GMT-0700 (Pacific Daylight Time)  - But this seems like a hack. What if it was GMT+ something instead of - something

使用$ .param（）编码日期重建日期的正确方法

0 个答案: