Question

我想在一个页面上显示3个表格。

我使用了3个不同的查询，但它在第二个查询中给出了错误。我假设这不是语法错误，但它可能是。如果您需要更多详细信息，请与我们联系。

代码，

<?php
session_start();
if ($_SESSION['loggedin'] != "YES")
{
    header("location:index.php?problem=notLoggedIn");
}
$name = $_SESSION['username'];
?>
<html>
<div style="width: 80%; margin-left:auto; margin-right:auto;">
<div style="float: right;">Welcome <? print($name); ?></div>
<?php 
//Connect to MSSQL Server
$myServer = ".\MSSQLSERVER2008";
$myUser = "admin";
$myPass = "password";
$myDB = "database"; 

//connection to the server
$dbhandle = mssql_connect($myServer, $myUser, $myPass)
  or die("Couldn't connect to SQL Server on $myServer"); 

  //select a database to work with
$selected = mssql_select_db($myDB, $dbhandle)
  or die("Couldn't open database $myDB");  

$result = mssql_query("SELECT *
FROM table1
INNER JOIN table4
ON table1.user_id=table4.user_id;");
if(!$result){
//echo 'Failed to receive data. Please try again, or contact support.';
}
else{
//echo 'Successfully received data.';
//$results = mssql_query($result);
//var_dump($results);
}
?>
<center>
<table border='1'>
    <tr>
        <th>Name of Center</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Name_of_Center'] . "</td>"; }
        mssql_data_seek($result, 0); ?> 
    </tr>
    <tr>
        <th>Contact Name</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Contact_Name'] . "</td>"; }
        mssql_data_seek($result, 0); ?> 
    </tr>
    <tr>
        <th>Title</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Title'] . "</td>"; }
        mssql_data_seek($result, 0); ?> 
    </tr>
    <tr>
        <th>Street Address</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Street_Address'] . "</td>"; }
        mssql_data_seek($result, 0); ?> 
    </tr>
    <tr>
        <th>City</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['City'] . "</td>"; }
        mssql_data_seek($result, 0); ?>
    </tr>
    <tr>
        <th>State</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['State_or_Province'] . "</td>"; }
        mssql_data_seek($result, 0); ?>
    </tr>
    <tr>
        <th>Zipcode</th>
        <?php while($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Zipcode'] . "</td>"; }
        mssql_data_seek($result, 0); ?>
    </tr>
    <tr>
        <th>Instructions</th>
        <?php while ($row = mssql_fetch_array($result)) {
        echo "<td>" . $row['Instructions'] . "</td>"; }
        mssql_data_seek($result, 0); ?>
    </tr>
</table>

<?php//insert form results into database
$result2 = mssql_query("SELECT *
FROM table2
INNER JOIN table4
ON tale2.user_id=table4.user_id;");
if(!$result2){
//echo 'Failed to receive data. Please try again, or contact support.';
}
else{
//echo 'Successfully received data.';
//$results = mssql_query($result);
//var_dump($results);
}?>

<table border='1'>
    <tr>
        <th>Last Name 1</th>
        <?php while($row2 = mssql_fetch_array($result2)) {
        echo "<td>" . $row2['Last_Name_1'] . "</td>"; }
        mssql_data_seek($result2, 0); ?>    
    </tr>
    <tr>
        <th>First Name 1</th>
        <?php while($row2 = mssql_fetch_array($result2)) {
        echo "<td>" . $row2['First_Name_1'] . "</td>"; }
        mssql_data_seek($result2, 0); ?>    
    </tr>
    <tr>
        <th>Mobile Phone 1</th>
        <?php while($row2 = mssql_fetch_array($result2)) {
        echo "<td>" . $row2['Mobile_Phone_1'] . "</td>"; }
        mssql_data_seek($result2, 0); ?>    
    </tr>
    <tr>
        <th> 3 Work Phone</th>
        <?php while($row2 = mssql_fetch_array($result2)) {
        echo "<td>" . $row2['Work_Phone_3'] . "</td>"; }
        mssql_data_seek($result2, 0); ?>    
    </tr>
    <tr>
        <th>3 Email</th>
        <?php while($row2 = mssql_fetch_array($result2)) {
        echo "<td>" . $row2['Email_3'] . "</td>"; }
        mssql_data_seek($result2, 0); ?>    
    </tr>
</table>

<?php//insert form results into database
$result3 = mssql_query("SELECT *
FROM table3
INNER JOIN table4
ON table3.user_id=table4.user_id;");
if(!$result3){
//echo 'Failed to receive data. Please try again, or contact support.';
}
else{
//echo 'Successfully received data.';
//$results = mssql_query($result);
//var_dump($results);
}?>

<table border='1'>
    <tr>
        <th>Insured Name</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Insured_Name'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>
    <tr>
        <th>Policy Number</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Policy_Number'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>
    <tr>
        <th>Specimen Number 5</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Specimen_Number_5'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>
    <tr>
        <th>Specimen Number 6</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Specimen_Number_6'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>
    <tr>
        <th>Premium 24</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Premium_24'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>   
    <tr>
        <th>Premium 25</th>
        <?php while($row3 = mssql_fetch_array($result3)) {
        echo "<td>" . $row3['Premium_25'] . "</td>"; }
        mssql_data_seek($result3, 0); ?>    
    </tr>
</table>
</center>
<style>
select {
    -webkit-appearance: none;
    -moz-appearance: none;
    text-indent: 1px;
    text-overflow: '';
}

select::-ms-expand {
    display: none;
}

td a:link {
 color:  white;
}

td a:visited {
 color: white;
} 

td a:active {
 color: white; 
} 
</style>

</html>

这是错误：

解析错误：语法错误，意外T_VARIABLE

这条线：

$result2 = mssql_query("SELECT *

Answer 1

$ result2查询中的JOIN子句包含“ON tale2.user_id = table4.user_id;”。我假设你的意思是table2.user_id而不是tale2.user_id？事实上，它不仅仅是一个假设，因为你从table2中选择，而不是tale2。（我会将此作为评论包含在内，但尚未达到声誉级别。）

Answer 2

改变这个：

<?php//insert form results into database
$result3 = mssql_query("SELECT *

......对此：

<?php
//insert form results into database
$result3 = mssql_query("SELECT *

编辑： <?php与代码或评论之间至少应有一个空格（在最后p之后）。

如果不这样做，将导致解析错误。

无效： <?php// comment

无效： <?phpecho "Hello";

相反：

有效： <?php // comment

有效： <?php echo "Hello";

PHP页面中的多个SQL查询

2 个答案: