Question

有没有办法打印出变量代表而不是变量？让我来说明一下这个想法：

E=[4,19,0,17,8]
G=[4,13,8,18,17]
F=[4,18,0,8,19]
D=[4,13,0,19,8]
lag = [E, G, F, D]
lcode = [4,19,0,17,8]

for i in lag:
    if i == lcode:
        print "This is", i

我想要印刷品说：“这是E”......而不是：“这是[4,19,0,17,8]”

Answer 1

这是使用dict

完成的方法

items = {"E": [1, 2, 3, 4, 5], "G": [1, 12, 13, 15] }
search = 4
for key, values in items.iteritems():
    if search in values:
        print key

输出：E

Answer 2

使用字典的想法。你可以这样做：

mydict = {"E":[4,19,0,17,8],"G":[4,13,8,18,17],"F":[4,18,0,8,19],"D":[4,13,0,19,8]}

for key,value in mydict.iteritems():
    if value == lcode:
        print "This is %s" %(i)

iteritems（）将字典元素分解为键值对，例如key：value ::“E”：[4,19,0,17,8]。

如果您要搜索所有列表中包含给定element的内容：

for key,value in mydict:
    if element in value:
        print "Element in %s " %(key)

因此，如果element为4，程序将打印：

Element in E
Element in G
Element in F
Element in D

Answer 3

没有创建Dict，你可以试试这个

import sys

    E=[4,19,0,17,8]
    G=[4,13,8,18,17]
    F=[4,18,0,8,19]
    D=[4,13,0,19,8]

    lcode = [4,19,0,17,8]

    modname = globals()['__name__']
    modobj  = sys.modules[modname]

    lag = ["E","G","F","D"]

    for name in lag:
        if lcode ==  getattr(modobj, name):
            print name

输出：E

如何打印变量代表变量？

3 个答案: