Question

在此SQL查询之后：

SELECT DISTINCT * 
    FROM ['Duplicate Data$']
    WHERE Name in
    (
        SELECT Name
        FROM ['Duplicate Data$']
        GROUP BY Name
        HAVING COUNT(*)>1
    )
    ORDER BY Name

我的表格如下：

    ID | Name
  20215 | A Abbott
  22015 | A Abbott
  11825 | A Albert
  20745 | A Albert
  14109 | A Allan
  19696 | A Allan
  13133 | A Allan
  17311 | A Allen

我需要查询此表，以便返回结果，如：

     ID | Name
  20215 | A Abbott
  11825 | A Albert
  13133 | A Allan

Answer 1

    SELECT MIN(ID),Name
    FROM ['Duplicate Data$']
    GROUP BY Name
    HAVING COUNT(*)>1
    ORDER BY Name

Answer 2

试试这个

SELECT * 
    FROM ['Duplicate Data$'] A
WHERE ID = (SELECT MIN(ID) 
            FROM ['Duplicate Data$'] X 
            WHERE A.NAME = X.NAME)

Answer 3

在子查询或CTE中使用由row_number()分区的name函数：

create table #t
   (ID int, Name varchar(10));
insert #t values
(  20215, 'A Abbott'),
(  22015, 'A Abbott'),
(  11825, 'A Albert'),
(  20745, 'A Albert'),
(  14109, 'A Allan'),
(  19696, 'A Allan'),
(  13133, 'A Allan'),
(  17311, 'A Allen');


select id, name
from (
    select *, row_number() over(partition by name order by id) rn from #t
) x
where rn = 1;

（最后一行中的“A Allen”是拼写错误，对吗？）

sql - 如果记录是重复集之一，则首先记录

3 个答案: