Question

这是我的PHP代码：

header('Content-type: application/json');
$con = mssql_connect('xx.xx.xx.xx\\MSSQLSERVER2012', 'user', 'password');
@mssql_select_db('mydbname') or die ("Error");

$username = $_POST['username'];
$query = "SELECT username,password FROM users WHERE username='$username'";
$result = mssql_query($query, $con) or die ("Error");
$num = mssql_num_rows($result);

$rows = array();

while ($r = mssql_fetch_assoc($result))

{
    $rows[] = $r;

if($_POST['username'] == $username)
{
    echo '{"success":1}';
}else
{
    echo '{"success":0,"error_message":"Username and/or password is invalid."}';
}
}echo json_encode($rows);

mssql_close($con);

和ios代码：

@try {

    if([[txtUsername text] isEqualToString:@""] || [[txtPassword text] isEqualToString:@""] ) {
        [self alertStatus:@"Please enter both Username and Password" :@"Login Failed!"];
    } else {
        NSString *post =[[NSString alloc] initWithFormat:@"KullaniciAdi=%@",[txtUsername text]];
        NSLog(@"PostData: %@",post);

        NSURL *url=[NSURL URLWithString:@"http://mysite/json/login.php"];

        NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

        NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
        [request setURL:url];
        [request setHTTPMethod:@"POST"];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:postData];

        [NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];

        NSError *error = [[NSError alloc] init];
        NSHTTPURLResponse *response = nil;
        NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

        NSLog(@"Response code: %d", [response statusCode]);
        if ([response statusCode] >=200 && [response statusCode] <300)
        {
            NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
            NSLog(@"Response ==> %@", responseData);                    

            SBJsonParser *jsonParser = [SBJsonParser new];
            NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:responseData error:nil];


            NSLog(@"%@",jsonData);



            NSInteger success = [(NSNumber *) [jsonData objectForKey:@"success"] integerValue];




            NSLog(@"%d",success);
            if(success == 1)
            {
                NSLog(@"Login SUCCESS");
                [self alertStatus:@"Logged in Successfully." :@"Login Success!"];

            } else {

                NSString *error_msg = (NSString *) [jsonData objectForKey:@"error_message"];
                [self alertStatus:error_msg :@"Login Failed!"];
            }

        } else {
            if (error) NSLog(@"Error: %@", error);
            [self alertStatus:@"Connection Failed" :@"Login Failed!"];
        }
    }
}
@catch (NSException * e) {
    NSLog(@"Exception: %@", e);
    [self alertStatus:@"Login Failed." :@"Login Failed!"];
}

如果我使用mysql数据库工作正常，但msssql不行。如何从mssql中获取我的项目。我的json数据日志：

 [__NSArrayM objectForKey:]: unrecognized selector sent to instance 0x8c8bf50

如果我在php中删除了json编码，则响应为null。

Answer 1

如果没有看到你的mssql数据库发送的jsonBody，很难分清楚是怎么回事，但如果我不得不猜测，你就会因为这条线而遇到这个问题。

NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:responseData error:nil];

查看SBJson库，选择器objectWithString：可以返回NSDictionary或NSArray，所以如果你的json有效负载如下所示：

[{"record":1,"value":"record1"},{"record":2,"value":"record2"}]

然后objectWithString将返回一个数组，以便在您调用

时

NSInteger success = [(NSNumber *) [jsonData objectForKey:@"success"] integerValue];

你得到一个崩溃，用于将NSDictionary的选择器发送到NSArray。尝试这样的事情：

id parsedObject = [jsonParser objectWithString:responseData error:nil];
if ([parsedObject isKindOfClass:[NSDictionary class]]) {
   //Treat as a NSDictionary        


} else if ([jsonData isKindOfClass:[NSArray class]]) {
    //Treat as an array of NSDictionaries

}

我的PHP与mssql where子句不起作用

1 个答案: