Question

我有ArrayList<CustomObject> myFinalList = new ArrayList<CustomObject>(); 该列表具有列表中每个条目的ojbect属性“NumberOfLikes”。 “NumberOfLikes”是字符串值。

我将这些值派生成一个数组，如下所示： -

ArrayList<String> numberOfLikes = new ArrayList<String>();

        for(int j =0; j<myFinalList.size(); j++)
        {
            String likes = myFinalList.get(j).getNewsLikes();
            numberOfLikes.add(likes);
        }


        numberofLikesArray=  numberOfLikes.toArray(new String[numberOfLikes.size()]);

    int[] numberofLikesArrayInt = new int[numberofLikesArray.length];

    for (int n = 0; n < numberofLikesArray.length; n++) 
    {
        numberofLikesArrayInt[n] = Integer.parseInt(numberofLikesArray[n]);
    }
    Arrays.sort(numberofLikesArrayInt);
    ArrayList<Integer> intAarrylistlikes = new ArrayList<Integer>();
    for (int i = 0; i < numberofLikesArrayInt.length; i++) 
    {
        intAarrylistlikes.add(numberofLikesArrayInt[i]);
    }
    Collections.reverse(intAarrylistlikes);
    numberofLikesArrayInt = convertIntegers(intAarrylistlikes);
    numberofLikesArray = Arrays.toString(numberofLikesArrayInt).split("[\\[\\]]")[1].split(", ");

    for (int i = 0; i < numberofLikesArray.length; i++) 
    {
        companyNewsList = Lists.newArrayList(Collections2.filter(myFinalList, new ArticleFilter2(numberofLikesArray[i])));
    }

ArticleFilter2.java

public class ArticleFilter2 implements Predicate<News>
{
    private final Pattern pattern;

    public ArticleFilter2(final String regex)
    {
        pattern = Pattern.compile(regex);
    }

    @Override
    public boolean apply(final CustomObject input)
    {
        return pattern.matcher(input.getLikes()).find();
    }
}

现在这个数组按降序排列“NumberOfLikes”。现在我想创建另一个ArrayList，根据这些值对“MyFinalList”进行排序，即： - 具有最大喜欢的项目应首先出现。

我该怎么做？

Answer 1

这要求您使用自定义类Comparator。 http://docs.oracle.com/javase/7/docs/api/java/util/Comparator.html

创建一个实现Comparator的新类并实现此方法：

public class YourComparator<CustomClass> implements Comparator{
    @Override
    public int compare ( CustomClass obj1, CustomClass obj2 ) {
        return (int) (obj1.getYourProperty() - obj2.getYourProperty());
    }
}

使用它：

Collections.sort(MyFinalList, new YourComparator());

基于on对象属性对ArrayList进行排序

1 个答案: