Question

我想将日志文件中的行复制到单独的文件中。它应该只复制那些包含给定列表中ip的行。

//编辑 - 更详细的测试代码这是我的代码：

static String[] ips = [
"192.168.1.2",
"192.168.1.1"
];

public static void main(String[] args) {

    AntBuilder ant = new AntBuilder();

    String folder = 'C:/logs';

    ips.each {
        String ip = it;
        File file = new File("${folder}/singular_incidents/${ip}.txt")
        ant.copy(tofile:"${folder}/singular_incidents/${ip}.txt"){
            fileset(dir: folder){
                include(name:"*access*.log")
            }
            filterchain(){
                linecontains(){
                    contains(ip)
                }
            }
        }
    }
}

AND日志文件（accesslog-2014-05-05.log）内容可能如下所示

192.168.1.1 - user1 [24/Apr/2014:15:51:06 +0200] 'GET HTTP/1.1' 192.168.1.1 - user1 [24/Apr/2014:15:51:38 +0200] 'POST ' 192.168.1.2 - user2 [24/Apr/2014:15:51:40 +0200] 'POST ' 192.168.1.3 - user3 [24/Apr/2014:16:60:40 +0200] 'POST '

目标是我应该获得两个带名字的单独文件 - 192.168.1.1.txt - 包含两个第一行 - 192.168.1.2.txt - 包含第三行

不幸的是，当使用linecontains时，我收到此错误（我已经混淆了实际的ip字符串）：

Caught: class org.apache.tools.ant.filters.LineContains$Contains doesn't support nested text data ("555.555.555.555")

Answer 1

希望这有助于你：

String[] ips = [
    "192.168.1.2",
    "192.168.1.1"
]

def ant = new AntBuilder()
def dest = new File('/tmp')
new File('.').eachFileMatch(~/access.*.log/) { log ->
   ips.each { ip ->
        File file = new File(dest, "${ip}.txt")
        ant.copy(file: log.name, tofile: "$dest.absolutePath/${ip}.txt") {
            filterchain() {
                linecontains() {
                    contains(value: "$ip")
                }
            }
        }
    } 
}

Groovy Ant - Filterchain Line包含错误

1 个答案: