Question

在我的域名中，我有一个名为＆＃34; Block＆＃34;的对象。 A＆＃34; Block＆＃34;可以拥有＆＃34; Pins＆＃34;和＆＃34;属性＆＃34;附在它上面。

我可以创建两个组，它们给我以下结果：

Group1是：

Block:B1
    Pin:P1
    Pin:P2
Block:B2
    Pin:P3
    Pin:P4

Group2是：

Block:B1
    Attribute:Att1, Value: Value1
    Attribute:Att2, Value: Value2
Block:B2
    Attribute:Att3, Value: Value3
    Attribute:Att4, Value: Value4

现在我想把这两个结果合并成这样的结果：

结果组是：

Block:B1
    Pin:P1
    Pin:P2
    Attribute:Att1, Value: Value1
    Attribute:Att2, Value: Value2
Block:B2
    Pin:P3
    Pin:P4
    Attribute:Att3, Value: Value3
    Attribute:Att4, Value: Value4

LINQ可以实现吗？或者我是否需要取消分组结果才能在以后创建分组结果？

由于

编辑：使用Road242解决方案，我得到了这个结果：

Pin: P1
Pin: P2
Attribute: Att1
Attribute: Att2
Pin: P3
Pin: P4
Attribute: Att3
Attribute: Att4

引脚和属性看起来很不错，但我把这些块丢失为分组键： - （

编辑：我的查询看起来像这样：

var blockPinsQuery = from blockPinRelation in blockPinRelations
            join block in blocks
                on blockPinRelation.BlockId equals block.Id
            join pin in pins
                on blockPinRelation.PinId equals pin.Id
            group pin by block
            into g
            select new
                   {
                       Block = g.Key,
                       Pins = g
                   };

和

var blockAttributesQuery = from blockAttributeRelation in blockAttributeRelations
                             join block in blocks
                                 on blockAttributeRelation.BlockId equals block.Id
                             join attribute in stringAttributes
                                 on blockAttributeRelation.AttributeId equals attribute.Id
                                   group attribute by block
                                 into g
                                 select new
                                 {
                                     Block = g.Key,
                                     Attributes = g
                                 };

如您所见，相关实体之间存在关系表。但我认为这并不重要。

我的输出例程如下所示：

foreach (var group in blockPinsQuery)
        {
            Console.WriteLine("Block:" + group.Block.Name);
            group.Pins.ToList().ForEach(x => Console.WriteLine("\t" + "Pin:" + x.Name));
        }

和

foreach (var group in blockAttributesQuery)
        {
            Console.WriteLine("Block:" + group.Block.Name);
            group.Attributes.ToList().ForEach(x => Console.WriteLine("\t" + "Attribute:" + x.Name + ", " + "Value: " + x.Value));
        }

和Road242查询：

foreach (var group in joinedResults)
        {
            group.Pins.ToList().ForEach(p => Console.WriteLine("Pin: " + p.Name));
            group.Attributes.ToList().ForEach(p => Console.WriteLine("Attribute: " + p.Name));
        }

Answer 1

你可以使用linq join子句：

请参阅http://msdn.microsoft.com/en-us/library/bb311040.aspx

var joinedResults =
    from g1 in Group1
    join g2 in Group2 on g1.Block equals g2.Block
    select new { Pin = g1.Pin, Attribute = g2.Attribute };

LINQ合并了两个分组的查询结果

1 个答案: