Question

我想创建一个反序列化序列化类的方法。

代码：

Settings newSettings = new Settings(); //Settings is a class.
Settings lastSettings = new Settings();
private void LoadXML(Type type,string filepath)
{
XmlSerializer serializer = new XmlSerializer(type);
FileStream fs = File.Open(filepath,FileMode.Open);
Settings newset = (Settings)serializer.Deserialize(fs); //Deserializes a serializable class file.
newSettings = newset; //Sets these settings as NewSettings
lastSettings = newSettingsXML; //Before form opening, sets information into form.
fs.Close();
}

现在我想用方法做这些。我为“人”类创建了不同的方法。此方法从xml文件中读取人员并将这些人员设置为表单。

private void PersonFromXML(string filepath)
{
XmlSerializer serializer = new XmlSerializer(typeof(BindingList<Person>));
FileStream fs = File.Open(filepath,FileMode.Open);
BindingList<Person> XML_Person = (BindingList<Person>)serializer.Deserialize(fs);
NEW_XML_Person = XML_Person; // These are BindingList<Person>.
fs.Close();
Grid_Person.DataSource = XML_Person;
}

我想将这些反序列化方法作为一个不同的方法。我想将此方法写入dll文件。我试着这样做：

private BindingList<Type> FromXML(BindingList<Type> type,string filepath)
{
XmlSerializer ser = new XmlSerializer(typeof(type));
FileStream fs = File.Open(filepath,FileMode.Open);
BindingList<Type> BL = (type)ser.Deserialize(fs);
fs.Close();
return BL;
}

但它没有用。因为我无法将BindingList类型设置为Person ..我该怎么办？感谢。

Answer 1

似乎您忘记在方法声明中设置泛型类型参数。

试试这个：

public static class MySerializationHelper
{
   public static class From
   {
      public TReturn XMLFile<TReturn>(string contents)
      {
         var serializer = new XmlSerializer(typeof(TReturn));
         var fs = File.Open(filePath, FileMode.Open);
         var result = (TReturn)serializer.Deserialize(fs);
         fs.Close();
         return result;
      }
   }

   public static class To
   {
      public void XMLFile<TType>(TType object, string filePath)
      {
         // Serialize it here...
      }
   }
}

然而，您可以简单地使用它，例如：

var bindingList = MySerializationHelper.From.XmlFile<IBindingList<Person>>("Persons.xml");
var person = MySerializationHelper.From.XmlFile<Person>("Person_1.xml");

MySerializationHelper.To.XmlFile<IBindingList<Person>>(bindingList, "Persons_copy.xml");
MySerializationHelper.To.XmlFile<Person>(person, "Person_1_Copy.xml");

创建一个反序列化序列化对象的方法。

1 个答案: