Question

当我将以下代码添加到我的html页面以获取java webapp时，页面上的脚本将退出响应。下面删除的代码段：

$("#btnCreateIng").click(function () {
    alert("clicked");
    var newName = document.getElementById("t_ingNameCreate").value;
    var newCategory = document.getElementById("t_ingCategoryCreate").value;
    var theData = "name=" + newName + "&" + "category=" + newCategory;
    alert("Sending: " + theData);
    var theUrl = "http://localhost:8080/webserv1/resources/ws2/ingredients/";
    $.ajax({
        url: theUrl,
        type: "POST",
        dataType: "text",
        contentType: "application/x-www-form-urlencoded",
        data: theData,
        success: function (result, status, jqxhr) {
            alert("success" + status);
            var ingArray = JSON.parse(result);
            alert(ingArray);
            var output = "<h3>Just Added</h3>";
            output += "<ul>";
            for (var i = 0; i < ingArray.length; i++) {
                output += "<li>" + ingArray[i].name + " (" + ingArray[i].id + "," ingArray[i].category + ")" + "</li>";
            }
            output += "</ul>";
            alert(output);
            $("#p_createIng").html(output);
        },
        error: function (xhr, status, errorthrown) {
            alert("error" + status + " e: " + errorThrown);
            $("#p_createIng").html("Error:" + xhr.status + " " + xhr.statusText);
        }
    });
});

允许脚本实际运行。我知道错误来自这里，但我无法找出错误。请帮忙。

Answer 1

output+="<li>" + ingArray[i].name+ "("+ingArray[i].id + "," + ingArray[i].category + ")"+"</li>";

你忘了一个'+'号。当然，如果在此语法错误修复后这不起作用 - 提供更多详细信息（请检查控制台）。

Java脚本错误导致脚本无法响应

1 个答案: