Question

我有一个像

这样的查询

 select distinct i.charge_type, cp.name, sum(i.amount)
 from charge.gp_schedule gp, charge.gsm_charge_plan i, charge cp
 where i.code = gp.sales_audit_code
 and cp.code = gp.code
 group by i.charge_type ,cp.name

输出例如以下

     GSMFixedCharge         FCFBBR15           15
     **GSMUsageCharge**    Call Charges       2.16
     **GSMUsageCharge**   Service Charges      2
     GSMFixedCharge         Line Rental       23.98
     GSMFixedCharge         FCFAFPBL            1

如何仅根据＆＃39; GSMUsageCharge＆＃39;进一步对值进行求和。在同一个查询中，所需的输出将是

     GSMFixedCharge  FCFBBR15          15
     GSMUsageCharge  Call Charges      4.16
     GSMFixedCharge  Line Rental      23.98
     GSMFixedCharge  FCFAFPBL           1

我尝试了类似

的内容

  select distinct i.charge_type, cp.name, DECODE(i.charge_type, 'GSMUsageCharge', sum (i.amount)    
   group by i.charge_type) result

但它不起作用......

Answer 1

您可以尝试以下查询。首先，为'** GSMUsageCharge **'修改i.charge_type和cp.name值。接下来，将金额相加。请注意，使用GROUP BY时不需要使用DISTINCT。

SELECT charge_type, name, sum(amount)
FROM
( select 
    CASE 
        WHEN i.charge_type = '**GSMUsageCharge**' THEN 'GSMUsageCharge'
        ELSE i.charge_type
    END charge_type,
    CASE 
        WHEN i.charge_type='**GSMUsageCharge**' AND cp.name='Service Charges' THEN 'Call Charges'
        ELSE cp.name
    END name,
    i.amount amount
 from charge.gp_schedule gp, charge.gsm_charge_plan i, charge cp
 where i.code = gp.sales_audit_code
 and cp.code = gp.code
) modified_names
group by charge_type, name;

Answer 2

我想进一步阐述上述评论。如果我错过了一些东西，你必须原谅我，我把它快速地扔在一起只是为了让你在一个可能正确的方向。我也习惯了MYSQL，所以如果我错过了任何细微差别，请告诉我：）

SELECT * FROM (
     (
     select distinct i.charge_type, cp.name, sum(i.amount)
     from charge.gp_schedule gp, charge.gsm_charge_plan i, charge cp
     where i.code = gp.sales_audit_code
     and i.charge_type <> '**GSMUsageCharge**'
     and cp.code = gp.code
     group by i.charge_type ,cp.name
     ) 
UNION 
     (
     select distinct i.charge_type, cp.name, sum(i.amount)
     from charge.gp_schedule gp, charge.gsm_charge_plan i, charge cp
     where i.code = gp.sales_audit_code
     and i.charge_type = '**GSMUsageCharge**'
     and cp.code = gp.code
     group by cp.name
     ) 
) result
ORDER BY name

如果值为oracle sql则求和

2 个答案: