Question

我有代码：

template<typename T>
void loadBrush_sub_impl()
{
    // do some work here
}

template<typename T, typename... Targs>
void loadBrush_sub()
{
    loadBrush_sub_impl<T>();
    loadBrush_sub<Targs...>();
}

template<>
void loadBrush_sub<void>()
{
}

// BasicBrush, BinaryBrush, SketchBrush, BasicEraser and MaskBased are class
loadBrush_sub<BasicBrush, BinaryBrush, SketchBrush, BasicEraser, MaskBased, void>();

编译时这是正确的。但是，我真的想放弃void中的loadBrush_sub<BasicBrush, BinaryBrush, SketchBrush, BasicEraser, MaskBased, void>();。

然而，这导致：

..\CanvasEngine\canvasengine.cpp: In instantiation of 'void loadBrush_sub() [with T = MaskBased; Targs = {}]':
..\CanvasEngine\canvasengine.cpp:36:5:   recursively required from 'void loadBrush_sub() [with T = BinaryBrush; Targs = {SketchBrush, BasicEraser, MaskBased}]'
..\CanvasEngine\canvasengine.cpp:36:5:   required from 'void loadBrush_sub() [with T = BasicBrush; Targs = {BinaryBrush, SketchBrush, BasicEraser, MaskBased}]'
..\CanvasEngine\canvasengine.cpp:114:81:   required from here
..\CanvasEngine\canvasengine.cpp:36:5: error: no matching function for call to 'loadBrush_sub()'
..\CanvasEngine\canvasengine.cpp:36:5: note: candidate is:
..\CanvasEngine\canvasengine.cpp:33:6: note: template<class T, class ... Targs> void loadBrush_sub()
..\CanvasEngine\canvasengine.cpp:33:6: note:   template argument deduction/substitution failed:
..\CanvasEngine\canvasengine.cpp:36:5: note:   couldn't deduce template parameter 'T'
mingw32-make[1]: *** [release/canvasengine.o] Error 1

我已经用enable_if做了一些实验，但没有幸运。是否有任何解决方案可以删除void并使编译器满意？

Answer 1

最简单的解决方案是添加另一个间接：

template<typename T>
void loadBrush_sub_impl()
{
    // do some work here
}

template<typename... Targs>
void loadBrush_sub();

template<typename T, typename... V>
void loadBrush_sub_helper()
{
    loadBrush_sub_impl<T>();
    loadBrush_sub<V...>();
}

template<typename... Targs>
void loadBrush_sub()
{
    loadBrush_sub_helper<Targs...>();
}

template<>
void loadBrush_sub<>()
{
}

Answer 2

没有助手（注意“=无效”）：

template<typename T>
void loadBrush_sub_impl()
{
    // do some work here
}

template<typename T = void, typename... Targs>
void loadBrush_sub();

template<typename T, typename... Targs>
void loadBrush_sub()
{
    loadBrush_sub_impl<T>();
    loadBrush_sub<Targs...>();
}

template<>
void loadBrush_sub<>()
{
}

Answer 3

您可能会专门使用辅助结构：

#include <iostream>

namespace Detail {
    template<typename T, typename... Targs>
    struct LoadBrush;

    template<typename T>
    struct LoadBrush<T> {
        static void sub() {
            std::cout << "Work\n";
        }
    };

    template<typename T, typename... Targs>
    struct LoadBrush {
        static void sub() {
            LoadBrush<T>::sub();
            LoadBrush<Targs...>::sub();
        }
    };
}

template<typename... Targs>
void loadBrush_sub()
{
    Detail::LoadBrush<Targs...>::sub();
}


struct BasicBrush {};
struct BinaryBrush {};
struct SketchBrush {};
struct BasicEraser {};
struct MaskBased {};

int main()
{
    loadBrush_sub<BasicBrush, BinaryBrush, SketchBrush, BasicEraser, MaskBased>();
    return 0;
}

Answer 4

另一种方法是使用 SFINAE。

#include <type_traits>
template<typename T>
void loadBrush_sub_impl()
{
    // do some work here
}

template<typename T>
void loadBrush_sub()
{
    loadBrush_sub_impl<T>();
}

template<typename T, typename... Ts>
std::enable_if_t<(sizeof...(Ts) > 0), void> 
loadBrush_sub()
{
    loadBrush_sub_impl<T>();
    loadBrush_sub<Ts...>();
}

如何匹配variadic模板中的空参数包

4 个答案: