Question

我使用curl通过API获取大量数据，这是代码：

function query($connectorGuid, $input, $userGuid, $apiKey, $additionalInput) {

          $url = "https://api.import.io/store/connector/" . $connectorGuid . "/_query?_user=" . urlencode($userGuid) . "&_apikey=" . urlencode($apiKey);

          $data = array("input" => $input);
          if ($additionalInput) {
            $data["additionalInput"] = $additionalInput;
          }

          $ch = curl_init($url);
          curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
          curl_setopt($ch, CURLOPT_POSTFIELDS,  json_encode($data));
          curl_setopt($ch, CURLOPT_POST, 1);
          curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
          curl_setopt($ch, CURLOPT_HEADER, 0);
          $result = curl_exec($ch);
          curl_close($ch);

          return json_decode($result, true);
        }

        // Query for tile Bundesliga Stats
        $result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
          "webpage/url" => "http://some_url.com/results_name/1234",
        ), $userGuid, $apiKey, false);
        var_dump($result);
}

我发布了整个代码，以防需要，但我真正需要的是最后一部分：

$result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
      "webpage/url" => "http:/some_url.com/result_name/1234",
    ), $userGuid, $apiKey, false);

有没有办法以某种方式将该URL设置为变量，然后将URL的“result_name”部分设置为另一个变量？

Answer 1

你发布了这个：

$result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
      "webpage/url" => "http://some_url.com/result_name/1234",
    ), $userGuid, $apiKey, false);

然后问这个：

有没有办法以某种方式将该URL设置为变量然后设置＆＃34; result_name＆＃34;另一个变量的URL的一部分？

你有什么理由不能这样做：

$URL/$result_name/1234

所以你的代码应该是这样的：

$URL = "http://some_url.com";
$result_name = "result_name";
$result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
      "webpage/url" => "$URL/$result_name/1234",
    ), $userGuid, $apiKey, false);

或许这可以让它更容易理解：

$URL = "http://some_url.com";
$result_name = "result_name";
$result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
      "webpage/url" => $URL . "/" . $result_name . "/1234",
    ), $userGuid, $apiKey, false);

或者嘿，看看1234。这些网址有很多部分。那么为什么不这样做呢：

// Create a URL array for all of the parts.
$URL_array = array();
$URL_array[] = "some_url.com";
$URL_array[] = "result_name";
$URL_array[] = "1234";

// Then set the result and use `implode` to create a coherent string from that URL array.
$result = query("73df0478-4e6e-4f78-9ab5-f9866ac7a531", array(
      "webpage/url" => "http://" . implode("/", $URL_array),
    ), $userGuid, $apiKey, false);

如何从PHP中获取URL中的字符串

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