Php试图在break语句中插入一个break行

Question

代码

查看第二个回应下的第二个回声

do {
    echo "<strong>Topic:". $row_AllTopics['topic'] . "</strong><br>";

    mysql_select_db($database_Select, $Select);
    $query_Comments = sprintf("SELECT * FROM comments where ((event_id=%s) AND (topic_id=%s)) ", $_POST['event_id'], $row_AllTopics['id']);
    $Comments = mysql_query($query_Comments, $Select) or die(mysql_error());
    $row_Comments = mysql_fetch_assoc($Comments);
    $totalRows_Comments = mysql_num_rows($Comments);

    do {
        // This is the echo in question.
        echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "\n";
    } while ($row_Comments = mysql_fetch_assoc($Comments));


} while ($row_AllTopics = mysql_fetch_assoc($AllTopics));

---

输出

（此文字全部居中对齐在屏幕上）

Topic:computer
linuxPosted by: andy linuxPosted by: andy Topic:computer
Posted by: Topic:ji
poPosted by: andy Topic:drive
makPosted by: andy Topic:new
nicePosted by: andy Topic:golf
holePosted by: andy plPosted by: andy

Answer 1

而不是\n，请尝试使用<br>。

Answer 2

您可以在PHP中使用nl2br（）函数：

echo nl2br($row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "\n");

这会将\n转换为<br/>。

Answer 3

"\n"将导致源代码中的换行符。虽然您的浏览器将呈现html，但您需要使用HTML换行符（<br>或<br />），这将给出预期的结果。

所以，你的代码将是这样的：

之前： echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "\n";

之后： echo $row_Comments['comment'] . "Posted by: ". $row_Comments['poster'] . "<br />";