public double calculateStdErrorEst()
{
double see = 0;
double residualSquare = 0;
CultureInfo culture = new CultureInfo("en-US");
List<double> residualTotal = new List<double>();
try
{
for (int i = 0; i < stockPctReturns.Count; i++)
{
// square root of all sums of predicted - actual or market - stock
residualSquare = Math.Sqrt(Convert.ToDouble((marketPctReturns.ElementAt(i) - stockPctReturns.ElementAt(i)), culture));
residualTotal.Add(Math.Round(residualSquare, 2, MidpointRounding.AwayFromZero));
}
see = residualTotal.Sum() / (stockPctReturns.Count - 2);
see = Math.Sqrt(see);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
return Math.Round(see, 2, MidpointRounding.AwayFromZero);
}
正如你所看到的,我试图将数值减少,以便我可以保持较小的数字与他们一起工作,但不管我尝试过什么,我一直得到NaN
作为唯一的结果。我在这里错过了什么吗?
答案 0 :(得分:4)
您可能尝试从负值获取平方根,这会导致Math.Sqrt
返回double.NaN
。在致电Math.Abs
之前使用Math.Sqrt
:
residualSquare = Math.Sqrt(Math.Abs(Convert.ToDouble((marketPctReturns.ElementAt(i) - stockPctReturns.ElementAt(i)), culture)));