我有一个程序将txt文档的行设置为Jlabel。在点击JButton时,它应该显示txt文件中的下一行,
问题是程序显示第一行并正常运行,但从不显示另一行。它允许我保持点击按钮但从不切换线...
这是我的代码。
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.*;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.*;
import javax.swing.*;
public class Driver {
List<String> lines;
static String line = "";
static Scanner scanner = new Scanner(System.in);
String s = "Welcome Students!";
String b = "Start!";
private JFrame f;
private JPanel p;
JFrame frame = new JFrame();
JButton b1 = new JButton(b);
JLabel jl = new JLabel(s);
int i;
private int clicked;
public Driver() {
gui();
}
public void gui() {
lines = readLinesFromFile();
i = 0;
f = new JFrame("Flash Card Program");
p = new JPanel();
f.setLayout(new GridLayout(2, 1));
f.add(jl);
f.add(p);
p.setLayout(new GridLayout(2, 1));
p.add(b1);
jl.setHorizontalAlignment(JLabel.CENTER);
// pack the frame for better cross platform support
f.pack();
// Make it visible
f.setVisible(true);
f.setSize(500, 400); // default size is 0,0
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
b1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
jl.setText(lines.get(i));
i++;
if ( i > lines.size() ) {
i = 0;
}
if (b1.getText().equals("Click For Answer")) {
b1.setText("Next Question");
} else {
b1.setText("Click For Answer");
}
}
});
b1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
if (clicked++ == 10) {
Object[] options = { "No, thanks", "Yes, please" };
int response = JOptionPane.showOptionDialog(frame,
"Would you like more math questions? ",
"Math Questions", JOptionPane.YES_NO_CANCEL_OPTION,
JOptionPane.QUESTION_MESSAGE, null, options,
options[1]);
if (response == 1)
clicked = 1; // reset
else
System.exit(0);
}
}
});
}
public static List<String> readLinesFromFile() {
List<String> lines = new ArrayList<String>();
try {
scanner = new Scanner(new File("upload.txt"));
if (scanner.hasNext()){
lines.add(scanner.nextLine());
}
} catch (FileNotFoundException e) {
e.printStackTrace();
}
return lines;
}
private static void readFile(File file) throws FileNotFoundException{
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
line = scanner.nextLine();
}
scanner.close();
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
new Driver();
readFile(new File("upload.txt"));
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
});
}
}
答案 0 :(得分:2)
好的,穷人的救援调试员:
public static List<String> readLinesFromFile() {
List<String> lines = new ArrayList<String>();
try {
// !! scanner = new Scanner(new File("upload.txt"));
scanner = new Scanner(new File(UPLOAD_TXT));
if (scanner.hasNext()) {
lines.add(scanner.nextLine());
}
} catch (FileNotFoundException e) {
e.printStackTrace();
}
System.out.println(lines); // ***** I added this
return lines;
}
它只读一行。然后我回头看看为什么:你使用 if 阻止而不是 while循环 。
改变这个:
if (scanner.hasNext()) {
lines.add(scanner.nextLine());
}
到此:
// also it should be hasNextLine() not hasNext()
while (scanner.hasNextLine()) {
lines.add(scanner.nextLine());
}
所以再次教训是:仅仅因为你的代码编译并不意味着它没有bug。使用简单的调试技术(如println语句(再次,“穷人的调试器”)通常只需要找到逻辑错误。功能强大的Eclipse调试器可以帮助您找到更多。
另外,您还需要更改此内容:
if (i > lines.size()) {
i = 0;
}
到此:
if (i >= lines.size()) {
i = 0;
}
避免数组超出范围异常。
此外,您的静态readFile(...)
方法和静态行变量没有用处。