我正在为我正在参加的C ++课程制作康威的生命游戏，而我似乎无法让它保持在边界的范围内。我们正在使用一个古老的类，所以它的解释如下。
<lvp\matrix.h> - 允许重新调整大小的二维数组
用法 -
声明 - matrix<itemType> itemName(numRows, numColumns, fillValue)
传递给函数 - (itemName)
参数 - (const matrix<itemType> &name)或前面没有'const'的参数。
所以这是一个问题的图片（向量是一个基于矩阵的类，它生成数组，并且有方法可以很容易地重新调整大小）。
http://imageshack.com/a/img835/2531/03gx.png
请记住我是一名初学程序员，所以请对你的批评保持温和：）
提前谢谢你。
所以这是迄今为止的代码：
#include <lvp\matrix.h>
#include <iostream.h>
//--------------------------------------------------------------
void displayBoard(const matrix<char> &board)
{
cout << " 1 2 3 4 5 6 7" << endl;
for( int row=0; row<board.numrows(); row++)
{
cout << row+1 << " ";
for( int col = 0; col < board.numcols(); col++)
cout<<"["<<board[row][col]<<"]";
cout<<endl;
}
}
//--------------------------------------------------------------
void placeLiveCells(matrix<char> &board, matrix<char> &check)
{
//Test function
board[3][3]='X';
board[3][4]='X';
board[3][2]='X';
check[3][3]='X';
check[3][4]='X';
check[3][2]='X';
}
//--------------------------------------------------------------
//--------------------------------------------------------------
void checkNeighbors(matrix<char> &board, int row, int col)
{
int count=0;
for(int i=0; i<2; i++)
{
if(board[row][col+1]=='X')
count++;
if(board[row][col-1]=='X')
count++;
if(board[row+1][col+1]=='X')
count++;
if(board[row-1][col-1]=='X')
count++;
if(board[row+1][col-1]=='X')
count++;
if(board[row-1][col+1]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row-1][col]=='X')
count++;
if(count<2)
board[row][col]='O';
if(count>3)
board[row][col]='O';
}
}
//--------------------------------------------------------------
void findX(matrix<char> &board)
{
int numspots=board.numrows()*board.numcols(), r=0, c;
for(int j=0; j<numspots; j++)
{
if(board[r][c]=='X')
checkNeighbors(board, r, c); /*This is where I think the
problem is, the code was working ok before I added this function*/
if(c==6)
{
c=0;
r++;
}
}
}
//--------------------------------------------------------------
int main()
{
int row=0, col=0;
matrix<char> check(7, 7, 'O');
matrix<char> board(7, 7, 'O');
displayBoard(board);
placeLiveCells(board, check);
displayBoard(board);
findX(board);
checkNeighbors(board, row, col);
return(0);
}
我对checkNeighbors的下一次尝试包括检查超出范围的错误＆lt; 0，但仍然无效：
void checkNeighbors(matrix<char> &board, int row, int col)
{
int count=0;
for(int i=0; i<2; i++)
{
if((row-1>=0) && (col-1>=0))
{
if(board[row][col+1]=='X')
count++;
if(board[row][col-1]=='X')
count++;
if(board[row+1][col+1]=='X')
count++;
if(board[row-1][col-1]=='X')
count++;
if(board[row+1][col-1]=='X')
count++;
if(board[row-1][col+1]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row-1][col]=='X')
count++;
if(count<2)
board[row][col]='O';
if(count>3)
board[row][col]='O';
}
else if((row-1<0) && (col-1>=0))
{
if(board[row][col+1]=='X')
count++;
if(board[row][col-1]=='X')
count++;
if(board[row+1][col+1]=='X')
count++;
if(board[row][col-1]=='X')
count++;
if(board[row+1][col-1]=='X')
count++;
if(board[row][col+1]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row][col]=='X')
count++;
if(count<2)
board[row][col]='O';
if(count>3)
board[row][col]='O';
}
else if((row-1>=0) && (col-1<0))
{
if(board[row][col+1]=='X')
count++;
if(board[row][col]=='X')
count++;
if(board[row+1][col+1]=='X')
count++;
if(board[row-1][col]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row-1][col+1]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row-1][col]=='X')
count++;
if(count<2)
board[row][col]='O';
if(count>3)
board[row][col]='O';
}
else if((row-1<0) && (col-1<0))
{
if(board[row][col+1]=='X')
count++;
if(board[row][col]=='X')
count++;
if(board[row+1][col+1]=='X')
count++;
if(board[row][col]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row][col+1]=='X')
count++;
if(board[row+1][col]=='X')
count++;
if(board[row][col]=='X')
count++;
if(count<2)
board[row][col]='O';
if(count>3)
board[row][col]='O';
}
}
}
所以我在这里所做的就是用if if语句重新编写checkNeighbors并使用if语句来检查其他单元格。他们现在做到这一点，如果row或col是负数，在检查相邻单元格时，它将不会-1到它将产生负数。