Question

我正在尝试创建一个CTE，它调用另一个CTE，如下所示。但是我得到了这个错误：

Msg 102，Level 15，State 1，Line 54'''附近的语法不正确。

我真的不知道问题是什么。我检查了一些类似于我和他的其他问题。尝试了那些解决方案，但由于某种原因它不会起作用。

With SEASONALITY_AVG_REVENUE
(
    YearKey
    ,Aggregation_Key
    ,Yearly_Avg_Revenue
)   
as
(
    SELECT
        ts.YearKey,
        agg.Aggregation_Key,
        Yearly_Avg_Revenue = AVG(agg.Revenue)

    FROM 
        seasonality_custom.TIME_SERIES_INDEX ts
        INNER JOIN seasonality_custom.SEASONALITY_AGG_TIME_SERIES agg
        ON ts.TIME_SERIES_INDEX = agg.TIME_SERIES_INDEX
    GROUP BY
        ts.YearKey,
        agg.Aggregation_Key  
)
, SEASONALITY_ALL_RECS
(
    YearKey
    ,Aggregation_Key
    ,Revenue
    ,Yearly_Avg_Revenue
)   
as
(
    SELECT
        ts.YearKey,
        agg.Aggregation_Key,
        agg.Revenue,
        Yearly_Avg_Revenue = savg.Yearly_Avg_Revenue
    FROM 
        seasonality_custom.TIME_SERIES_INDEX ts
        INNER JOIN seasonality_custom.SEASONALITY_AGG_TIME_SERIES agg
        ON ts.TIME_SERIES_INDEX = agg.TIME_SERIES_INDEX
        INNER JOIN SEASONALITY_AVG_REVENUE savg
        ON ts.YearKey = savg.YearKey and agg.Aggregation_Key = savg.Aggregation_Key
);

Answer 1

您不能拥有with语句，除非您通过其他语句（通常为select），但在许多数据库update和delete中也是如此。

您的语句有多个CTE，但它没有主要查询部分。错误在分号上，因为它终止了查询。

Answer 2

你真的需要一个CTE

; With SEASONALITY_AVG_REVENUE(YearKey, Aggregation_Key, Yearly_Avg_Revenue)   
AS
 (
SELECT  ts.YearKey,
        agg.Aggregation_Key,
        Yearly_Avg_Revenue = AVG(agg.Revenue)

FROM seasonality_custom.TIME_SERIES_INDEX ts INNER JOIN 
seasonality_custom.SEASONALITY_AGG_TIME_SERIES agg
ON ts.TIME_SERIES_INDEX = agg.TIME_SERIES_INDEX
GROUP BY ts.YearKey, agg.Aggregation_Key  
  )

SELECT ts.YearKey,
        agg.Aggregation_Key,
        agg.Revenue,
        Yearly_Avg_Revenue = savg.Yearly_Avg_Revenue
FROM seasonality_custom.TIME_SERIES_INDEX ts
INNER JOIN  seasonality_custom.SEASONALITY_AGG_TIME_SERIES agg
ON ts.TIME_SERIES_INDEX = agg.TIME_SERIES_INDEX
INNER JOIN SEASONALITY_AVG_REVENUE savg
ON ts.YearKey = savg.YearKey and  agg.Aggregation_Key = savg.Aggregation_Key

或

正如Gordon所说，CTE需要后跟SELECT，UPDATE，DELETE语句。

使用您当前的查询，您只需在第二个CTE的末尾选择，它也会返回相同的结果，但这将是一个不必要的步骤。像这样......

;WITH CTE1 (Col1, Col2) AS ( -- Some code here ), CTE2 AS ( -- Some code here ) SELECT * FROM CTE2

使用调用另一个CTE的CTE - 附近的语法不正确;

2 个答案: