使用scopt解析Scala选项

时间:2014-05-02 18:10:22

标签: scala scopt

使用scopt https://github.com/scopt/scopt

我有一个非常简单的Scala CLI驱动程序,它在.parse的第一行出错。该行是var i = 0,无法想象为什么会失败,也许是我如何实例化OptionParser?

def parse(args: Seq[String], init: C): Option[C] = {
  var i = 0 <———————————————— prints the error below
  val pendingOptions = ListBuffer() ++ (nonArgs filterNot {_.hasParent})

Exception in thread "main" java.lang.NoSuchMethodError: scala.runtime.IntRef.create(I)Lscala/runtime/IntRef;
at scopt.OptionParser.parse(options.scala:306)
at org.apache.mahout.drivers.ItemSimilarityDriver$.main(ItemSimilarityDriver.scala:47)
at org.apache.mahout.drivers.ItemSimilarityDriver.main(ItemSimilarityDriver.scala)

完整的代码在这里,对不起,但我是Scala的新手所以这可能是一个非常愚蠢的问题

object ItemSimilarityDriver {
  /**
   * @param args  Command line args, if empty a help message is printed.
   * @return
   */

def main(args: Array[String]): Unit = {

    val parser = new OptionParser[Config]("ItemSimilarity") {
      head("ItemSimilarity", "Spark")
      opt[Unit]('r', "recursive") action { (_, c) =>
        c.copy(recursive = true) } text("The input path should be searched recursively for files that match the filename pattern (optional), Default: false.")
      opt[String]('o', "output") required() action { (x, c) =>
        c.copy(output = x) } text("Output is a path for all output (required)")
      opt[String]('i', "input") required()  action { (x, c) =>
        c.copy(input = x) } text("Input is a path for input, it may be a filename or dir name. If a directory it will be searched for files matching the -p pattern. (required)")
      note("some notes.\n")
      help("help") text("prints this usage text")
    }
    // parser.parse returns Option[C]
    parser.parse(args, Config()) map { config =>  <—————————— parser was created 
                                                  but this call fails in the parse
      // do stuff
      //val didIt = true
    } getOrElse {
      // arguments are bad, error message will have been displayed, throw exception, run away!
    }

  }

  case class Config(recursive: Boolean = false, input: String = null, output: String = null)

}

我也尝试过使用相同错误的可变选项方法。

1 个答案:

答案 0 :(得分:7)

问题似乎与Scala库版本和scopt不匹配。目前稳定的scopt 3.2.0交叉发布:

  • Scala 2.9.1
  • Scala 2.9.2
  • Scala 2.9.3
  • Scala 2.10
  • Scala 2.11

Scala 2.10和2.11工件使用sbt 0.12的交叉版本控制约定并使用_2.10后缀,因为Scala 2.10.x次要版本与Scala 2.10.0二进制兼容。换句话说,scopt_2.11不是scopt_2.10的更高版本。一个针对Scala 2.11.x进行编译,而另一个针对Scala 2.10.x进行编译。

我建议您尝试管理外部库。 sbt有一个插件可以为你生成IntelliJ项目。