Question

在我的应用中，用户可以注册，用户可以在锻炼上发布锻炼和评论。

我设计了以下资源和URI：

USERS
/users
/users/{id}

WORKOUTS
/workouts
/workouts/{id}

COMMENTS
/workouts{id}/comments
/workouts{id}/comments/{id}

由于/ workouts URI返回时间轴，我试图映射用户的锻炼，例如/ workouts？user = userId

我不知道如何通过@QueryParam区分get all collection和get collection，因为：

@GET
@Produces({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON})
public Practicas getPracticas() {
    List<Practica> listaPracticas = practicaDao.getPracticas();
    Practicas practicas = new Practicas();
    practicas.setPracticas(listaPracticas);
    return practicas;
}

@GET
@Produces({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON})
public Practicas getPracticasUsuario(@QueryParam("idUsuario") int idUsuario) {
    List<Practica> listaPracticas = practicaDao.getPracticasByUser(idUsuario);
    Practicas practicas = new Practicas();
    practicas.setPracticas(listaPracticas);
    return practicas;
}

抛出以下异常：

org.glassfish.jersey.server.model.ModelValidationException: Validation of the application resource model has failed during application initialization.
[[FATAL] A resource model has ambiguous (sub-)resource method for HTTP method GET and input mime-types as defined by @Consumes and @Produces annotations at Java methods public com.sporty.model.Practicas com.sporty.resource.PracticasResource.getPracticas() and public com.sporty.model.Practicas com.sporty.resource.PracticasResource.getPracticasUsuario(int) at matching regular expression /practicas. These two methods produces and consumes exactly the same mime-types and therefore their invocation as a resource methods will always fail.; source='org.glassfish.jersey.server.model.RuntimeResource@1cc465f']

解决方案是否在URI上添加了另一个级别，例如/ workouts / search？user = userId？

是否存在源自糟糕的URI设计的问题？

提前致谢

Answer 1

我认为你正在寻找类似的东西：

@GET
@Produces({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON})
public Practicas getPracticasUsuario(@QueryParam("idUsuario") Integer idUsuario) {
    final List<Practica> listaPracticas;
    if (idUsario != null) {
        practicaDao.getPracticasByUser(idUsuario);
    } else {
        practicaDao.getPracticas();
    }
    Practicas practicas = new Practicas();
    practicas.setPracticas(listaPracticas);
    return practicas;

}

由@QueryParam过滤的泽西@GET集合和@GET集合

1 个答案: