Question

任何人都可以解释我的错误吗？这是表格，位于名为genericwebpage.html的网页上

<form name = "quoted" form action = "genericwebpage.php" method="get">
<input id = "poster" type="text" name="poster" placeholder = "Credited Individual.">     <br>
<textarea class = "actual-quote" name = "actual-quote"placeholder = "Write the quote here!"></textarea><br><br>
<input id = "submit1" type="submit">
</form>

和继承人php，在genericwebpage.php上找到

<div class="wrapper">
<div class="submissions">
<div class="logo-logo"><h2>Generic.</h2></div>
<div class="top-submit"><?php echo $_GET['actual-quote']?></div>
<div class="poster"><?php echo $_GET['poster']?></div>
</div>

有人可以指导我在正确的方向上解决这个问题，我看到很多人使用isset但我不知道这是否适用于这种情况？

Answer 1

在textarea的名称和占位符之间放置至少一个空格。

Answer 2

PHP显示＆＃34;实际引用＆＃34;没有收到。这是因为你在namefield之后遗漏了一个空格。复制并粘贴它，这是正确的：

<form name = "quoted" form action = "genericwebpage.php" method="get">
<input id = "poster" type="text" name="poster" placeholder = "Credited Individual.">     <br>
<textarea class = "actual-quote" name = "actual-quote" placeholder = "Write the quote here!"></textarea><br><br>
<input id = "submit1" type="submit">
</form>

Answer 3

尝试使用isset()或empty()来检查值是否为空以避免php通知还在表单字段中的每个attr（占位符/名称）之间使用空格

<form name = "quoted" form action = "genericwebpage.php" method="get">
<input id = "poster" type="text" name="poster" placeholder = "Credited Individual.">     <br>
<textarea class = "actual-quote" name = "actual-quote" placeholder = "Write the quote here!"></textarea><br><br>
<input id = "submit1" type="submit">
</form>

PHP

<div class="wrapper">
<div class="submissions">
<div class="logo-logo"><h2>Generic.</h2></div>
<div class="top-submit"><?php echo (!empty($_GET['actual-quote']) ? $_GET['actual-quote'] : '');?></div>
<div class="poster"><?php echo (!empty($_GET['poster']) ? $_GET['poster'] :'');?></div>
</div>

当我尝试从我的HTML接收我的表单并将其放入我的PHP时出错

3 个答案: