Question

这是一个非常基本的java问题，我有一个字符串数组

String[] navTitles = new String[] {Home, HR, company, joiner, next};

这些标题显示在ListView中。单击第一个项目时，我必须显示某个列表，否则如果单击任何其他标题，我必须显示不同的列表。第一个（默认）列表应该是单击第一个项目时出现的列表。问题是，如果我点击标题，则会显示与下一个标题相关的列表。当我点击最后一个标题时出现错误： -

    05-02 04:47:38.787: E/AndroidRuntime(1490): java.lang.ArrayIndexOutOfBoundsException: length=5; index=5
05-02 04:47:38.787: E/AndroidRuntime(1490):     at com.abc.attini.Home.displayView(Home.java:600)

这是我的代码： -

for (int j = 0; j < navMenuTitles.length && j < iconColors.length; j++) {
    navDrawerItems.add(new NavDrawerItem(navMenuTitles[j], iconColors[j]));

}
adapter = new NavDrawerListAdapter(getApplicationContext(), navDrawerItems);
mDrawerList.setAdapter(adapter);

mDrawerList.setOnItemClickListener(new SlideMenuClickListener());




private class SlideMenuClickListener implements 
        ListView.OnItemClickListener {

}
    @Override
    public void onItemClick(AdapterView<?> parent, View view, 
                            int position,  long id) {

        // display view for selected nav drawer item
        displayView(position);
    }
}


private void displayView(int position) {
    Fragment fragment = null;

    if (position == 0) {
        fragment = new HomeFragment(SPHostUrl, encodedAccountName, 
                deviceAuthKey, usersname, avatarUrl, fullName, 
                getApplicationContext(), myFinalNewsList);

    } else {
        String myPosition = null;

        myPosition = navDrawerItems.get(position).getTitle(); //Line 600


        companyNewsList = Lists.newArrayList(Collections2.filter(myFinalNewsList, 
                new ArticleFilter(myPosition)));

        fragment = new HomeFragment(SPHostUrl, encodedAccountName, deviceAuthKey, 
                usersname, avatarUrl, fullName, getApplicationContext(), companyNewsList);

    }

Answer 1

尝试以下代码： -

发生错误，因为索引值达到索引以上。

private void displayView(int position) 
{
    Fragment fragment = null;
    position = position % length; //length of your array 

    if(position==0)
    {
        fragment = new HomeFragment(SPHostUrl,encodedAccountName,deviceAuthKey,usersname,avatarUrl, fullName,getApplicationContext(),myFinalNewsList);
    }
    else
    {
        String myPosition = null;

        myPosition =  navDrawerItems.get(position).getTitle(); //Line 600


        companyNewsList = Lists.newArrayList(Collections2.filter(myFinalNewsList, new ArticleFilter(myPosition)));
         fragment = new HomeFragment(SPHostUrl,encodedAccountName,deviceAuthKey,usersname,avatarUrl, fullName,getApplicationContext(),companyNewsList);

    }
}

上面的代码在我的最后工作正常，因为它在数组长度下建立位置。

从数组显示的下一项而不是预期值

1 个答案: