Question

我有一个搜索栏和一个包含3部电影的SQL数据库

Name:Star Wars: Description: Contains the word group
Name:301: Description: Contains the word group
Name:destroyer: Description: Contains the word group

但是，当我搜索单词＆＃34; group＆＃34;

时

我通常只得到一个结果：

这是我的PHP代码：

 if(!isset($_POST['search']))
{
    header("Location:index.php");

}

$search_sql="SELECT * FROM php_item WHERE Name LIKE '%".$_POST['search']."%' OR Description LIKE '%".$_POST['search']."%'";
$search_query = mysql_query($search_sql);
if(mysql_num_rows($search_query)!=0)
{

$search_rs= mysql_fetch_assoc($search_query);
 }


?>


          </p>
          <p>&nbsp; Search Results</p>
          <?php

          if(mysql_num_rows($search_query) != 0){
              do{ ?>

              <p>
              <?php echo $search_rs['Name']; ?>

             <?php     }while($searchr_rs=mysql_fetch_assoc($search_query));





          } else {
            echo "No Results Found";  
          }





          ?>

Answer 1

EDIT 在我的旧帖子＆amp;中将$ search_rs更改为$ searchr_rs;现在它会起作用

<?php
if(!isset($_POST['search']))
{
    header("Location:index.php");

}

$search_sql="SELECT * FROM php_item WHERE Name LIKE '%".$_POST["search"]."%'  OR Description LIKE '%".$_POST["search"]."%' ";
$search_query = mysql_query($search_sql);
//print_r($search_query);
if(!$search_query){
die(mysql_error());
}
if(mysql_num_rows($search_query)>0)
{
 echo '<p>&nbsp; Search Results</p>';

              while($searchr_rs=mysql_fetch_array($search_query))
              {

             echo ' <p>';
              echo $searchr_rs['Name'];
    echo '</p>';
                 }





          } else {
            echo "No Results Found";  
          }




?>

搜索栏仅显示1个项目

1 个答案: