Question

我有一个数据库，有两个表教程和地区教程与分区有一对一的关系。在教程中添加页面我试图获得地区列表。

所以我在TutorialsController中编写了代码

下面的添加方法

public function add() {
        if ($this->request->is('post')) {
            $this->Tutorial->create();
            if ($this->Tutorial->save($this->request->data)) {
                $this->Session->setFlash(__('The tutorial has been saved.'));
                return $this->redirect(array('action' => 'index'));
            } else {
                $this->Session->setFlash(__('The tutorial could not be saved. Please, try again.'));
            }
        }
        $districts = $this->Tutorial->District->find('list');
        $this->set(compact('districts'));
    }

我确保了

var $uses = array('Tutorial','District');

教程中的关系代码

public $belongsTo = array(
        'Districts' => array(
            'className' => 'Districts',
            'foreignKey' => 'districts_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
    );

仍然我遇到错误在行代码中的非对象上调用成员函数find（）

$districts = $this->Tutorial->District->find('list');

我使用了var $uses = array('Tutorial','District');

为什么还会出现这个错误？

Answer 1

删除var $uses = array('Tutorial','District');（模型关联时不必要）并编辑为 -

public $belongsTo = array(
        'District' => array( // remove 's'
            'className' => 'Districts',
            'foreignKey' => 'districts_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
    );

错误：在Cakephp中的非对象上调用成员函数find（）

1 个答案: