Rails link_to helper

Question

我的rails应用程序中有以下路径：

recipient_template DELETE /templates/:id/recipient/:recipient_type/:recipient_id(.:format) 

如果我的应用程序动态填充收件人类型和收件人ID，我如何在视图中为此特定路径创建链接。

修改

这是我的模型和route.rb文件

class Template < ActiveRecord::Base
     has_and_belongs_to_many :individuals
     has_and_belongs_to_many :groups

     def recipients
         {:groups => self.groups, :individuals => self.individuals}
     end
end

resources :templates do
    member do
        match 'recipient/:recipient_type/:recipient_id', :to => :recipient_remove, :via => :delete
    end
end

Answer 1

试试这个

在路径中传递recipient_type和recipient_id值以及模板ID

link_to "Delete Recipient", recipient_remove_path(template.id, recipient_type, recipient_id), method: :delete

在您的路线中

match 'recipient/:recipient_type/:recipient_id' => "controller#action", :as => :recipient_remove, :via => :delete

并且您应该在reciepient_id

中的收件人类型和收件人ID中传递收件人类名