Permissions links Owner Group Size Date Time Directory or file
-rwxr--r-- 1 User1 root 26 2012-04-12 19:51 MyFile.txt
drwxrwxr-x 3 User2 csstf 4096 2012-03-15 00:12 MyDir
我有模式匹配的问题,使用上述细节获取某些细节。我实际上需要写下shell脚本来获取以下细节。
我需要在这个问题中使用管道。当我ls -la | prog.sh
时,需要在下面显示详细信息。
我不了解的主要部分是如何使用sed
模式匹配。
1.读取的总行数。
2.不同用户(所有者)的总数。
3.拥有所有者执行权限的文件总数。
4.前三大目录。
这是我到目前为止所尝试的内容
#!/bin/bash
while read j
do
B=`sed -n '$=' $1`
echo "total number of lines read = $B"
done
答案 0 :(得分:0)
while循环逐行读取ls -la
的输出,您需要处理每一行并维护变量以获取所需信息。
以下是一个示例脚本,可帮助您入门:
#!/bin/bash
declare -i lineCount=0
declare -i executePermissionCount=0
# an array to keep track of owners
declare -a owners=()
# read each line into an array called lineFields
while read -r -a lineFields
do
# the owner is the third element in the array
owner="${lineFields[2]}"
# check if we have already seen this owner before
found=false
for i in "${owners[@]}"
do
if [[ $i == $owner ]]
then
found=true
fi
done
# if we haven't seen this owner, add it to the array
if ! $found
then
owners+=( "$owner" )
fi
# check if this file has owner execute permission
permission="${lineFields[0]}"
# the 4th character should be x
if [[ ${permission:3:1} == "x" ]]
then
(( executePermissionCount++ ))
fi
# increment line count
(( lineCount++ ))
done
echo "Number of lines: $lineCount"
echo "Number of different owners: ${#owners[@]}"
echo "Number of files with execute permission: $executePermissionCount"