Laravel“至少一个”现场要求验证

时间:2014-05-01 02:55:34

标签: php laravel laravel-4

所以我有这些字段的表格

{{ Form::open(array('url' => 'user', 'id' => 'user_create_form')) }}

    <div class="form-input-element">
        <label for="facebook_id">ID Facebook</label>
        {{ Form::text('facebook_id', Input::old('facebook_id'), array('placeholder' => 'ID Facebook')) }}
    </div>

    <div class="form-input-element">
        <label for="twitter_id">ID Twitter</label>
        {{ Form::text('twitter_id', Input::old('twitter_id'), array('placeholder' => 'ID Twitter')) }}
    </div>

    <div class="form-input-element">
        <label for="instagram_id">ID Instagram</label>
        {{ Form::text('instagram_id', Input::old('instagram_id'), array('placeholder' => 'ID Instagram')) }}
    </div>

{{ Form::close() }}

我想告诉Laravel,至少需要其中一个字段。如何使用Validator进行此操作?

$rules = array(
    'facebook_id'                   => 'required',
    'twitter_id'                    => 'required',
    'instagram_id'                  => 'required',
);
$validator = Validator::make(Input::all(), $rules);

3 个答案:

答案 0 :(得分:84)

尝试检出required_without_all:foo,bar,...,看起来应该为你做。引用他们的文件:

  

只有当所有其他指定字段都不存在时,验证字段才必须存在。


实施例

$rules = array(
    'facebook_id' => 'required_without_all:twitter_id,instagram_id',
    'twitter_id' => 'required_without_all:facebook_id,instagram_id',
    'instagram_id' => 'required_without_all:facebook_id,twitter_id',
);
$validator = Validator::make(Input::all(), $rules);

答案 1 :(得分:7)

**For automatic validation**

$rules = array(
    'facebook_id' => 'required_without_all:twitter_id,instagram_id',
    'twitter_id' => 'required_without_all:facebook_id,instagram_id',
    'instagram_id' => 'required_without_all:facebook_id,twitter_id',
);
$message = array(
    'facebook_id' => 'The facebook field is required when none of twitter / instagram are present.',
    'twitter_id' => 'The twitter field is required when none of facebook / instagram are present.',
    'instagram_id' => 'The instagram field is required when none of twitter / facebook are present.');

$validator = Validator::make(Input::all(), $rules, $message)->validate();

答案 2 :(得分:0)

使用此代码,我已经做到了

php artisan make:rule RequiredWithout

use Illuminate\Contracts\Validation\Rule;

class RequiredWithout implements Rule
{
    private $without = [];
    private $current_attribute = "";
    private $no_need = "";

    public function __construct($without)
    {
        if(is_string($without))
        {
            $this->without = [$without];
        }
        elseif(is_array($without))
        {
            $this->without = $without;
        }
        else
           throw new \Exception('$without must be array or string');
    }

    public function passes($attribute, $value)
    {
        $this->current_attribute = $attribute;
        $requests = request()->all();
        foreach ($this->without as $WO_i)
        {            
            if(array_key_exists($WO_i, $requests))
            {
                $this->no_need = $WO_i;
                return false;
            }
        }
        return true;
    }

    public function message()
    {
        return "the $this->current_attribute Field and $this->no_need Shouldn't be Exist in this request together";
    }
}

,然后在控制器中使用

'country_id' => ['nullable', 'exists:countries,id', new ValidCountryID(), new RequiredWithout('country_code')],
'country_code' => ['nullable', 'exists:countries,IsoCountryCode', new ValidCountryID(), new RequiredWithout('country_id')],