ggplot内部函数尽管deparse（替换

Question

我已经从http://www.ling.upenn.edu/~joseff/rstudy/plots/graphics/phila_bar.R获取了示例，并从http://www.ling.upenn.edu/~joseff/rstudy/summer2010_ggplot2_intro.html获取了一个命令（在此页面上搜索性别：名称）。我试图将命令放在一个函数中并尝试在变量名称周围调用函数而没有引号，但是尽管使用了替换（deparse ...：

phil <- structure(list(Name = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 
3L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L), .Label = c("Bucks County", "Delaware County", "Montgomery County", 
"Philadelphia County"), class = "factor"), Gender = structure(c(1L, 
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 
2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 
1L, 1L, 2L, 2L, 2L, 2L, 2L), .Label = c("Female", "Male"), class = "factor"), 
    value = c(15288L, 43054L, 25788L, 62853L, 33622L, 50792L, 
    27184L, 71321L, 43593L, 94877L, 32442L, 54872L, 43751L, 18346L, 
    25545L, 87732L, 46656L, 63640L, 39675L, 25468L, 43636L, 34558L, 
    59923L, 26979L, 17550L, 27492L, 71404L, 39946L, 50107L, 96580L, 
    24957L, 17433L, 31468L, 40585L, 53239L, 21899L, 62542L, 38352L, 
    47008L, 31485L), Level = structure(c(1L, 4L, 2L, 5L, 3L, 
    3L, 1L, 4L, 2L, 5L, 3L, 5L, 4L, 1L, 2L, 5L, 3L, 4L, 2L, 1L, 
    4L, 3L, 5L, 2L, 1L, 1L, 4L, 2L, 3L, 5L, 2L, 1L, 3L, 4L, 5L, 
    1L, 5L, 3L, 4L, 2L), .Label = c("LessHigh", "High", "SomeAssoc", 
    "Bachelors", "GradProf"), class = "factor")), .Names = c("Name", 
"Gender", "value", "Level"), class = "data.frame", row.names = c(3463L, 
3465L, 3466L, 3467L, 3468L, 3471L, 3473L, 3475L, 3478L, 3479L, 
8741L, 8742L, 8743L, 8746L, 8750L, 8751L, 8752L, 8754L, 8756L, 
8757L, 22925L, 22926L, 22927L, 22928L, 22929L, 22933L, 22937L, 
22938L, 22939L, 22940L, 25844L, 25845L, 25846L, 25847L, 25849L, 
25854L, 25855L, 25856L, 25858L, 25860L))


testfn = function(gdf, Level, value, Gender, Name){
    print(
    ggplot(gdf, aes(deparse(substitute(Level)), deparse(substitute(value)),
         color = deparse(substitute(Name)),
         linetype = deparse(substitute(Gender)),
         group = deparse(substitute(Gender)):deparse(substitute(Name))))+
       geom_point()+
       geom_line() 
    )
}

testfn(phil, Level, value, Gender, Name)
Error in deparse(substitute(Gender)):deparse(substitute(Name)) : 
  NA/NaN argument
In addition: Warning messages:
1: In deparse(substitute(Gender)):deparse(substitute(Name)) :
  numerical expression has 4 elements: only the first used
2: In deparse(substitute(Gender)):deparse(substitute(Name)) :
  numerical expression has 5 elements: only the first used
3: In eval(expr, envir, enclos) : NAs introduced by coercion
4: In eval(expr, envir, enclos) : NAs introduced by coercion
5: In deparse(substitute(Gender)):deparse(substitute(Name)) :
  numerical expression has 4 elements: only the first used
6: In deparse(substitute(Gender)):deparse(substitute(Name)) :
  numerical expression has 5 elements: only the first used
7: In eval(expr, envir, enclos) : NAs introduced by coercion
8: In eval(expr, envir, enclos) : NAs introduced by coercion
> 

哪里可能是问题所在。谢谢你的帮助。

Answer 1

你确定吗？ （看起来像移除deparse做了一些我认为可能不起作用的东西，实际上也有效： - ）

testfn = function(gdf, Level, value, Gender, Name) {

  gg <- ggplot(gdf, aes(x = substitute(Level),
                        y = substitute(value),
                        color = substitute(Name),
                        linetype = substitute(Gender),
                        group = substitute(Gender):substitute(Name)
  ))

  gg <- gg + geom_point()
  gg <- gg + geom_line() 

  print(gg)

}

testfn(phil, Level, value, Gender, Name)