如何在数据库中找到前5个重复值并获得5个结果？

Question

    id |  unqid
    ___|________
    1  |  v1
    2  |  v1
    3  |  v1
    4  |  v1
    5  |  v4
    6  |  v4
    7  |  v9
    8  |  v9
    9  |  v9
   10  |  v2
   11  |  v7

我需要获得最重复的值，限制为5，就像 V1 V9 V4 V2 V7

我已经尝试过这段代码，但没有显示任何内容

SELECT unqid, COUNT(*) TotalCount FROM votes GROUP BY unqid HAVING COUNT(*) > 1 ORDER BY COUNT(*) DESC

Answer 1

我不确定这是否只是Oracle的事情，如果这不适用于你，请道歉，但我会这样做

select unqid, TotalCount 
  from (
    select unqid, count(*) as TotalCount 
    from votes 
    group by unqid
    order by TotalCount desc
  )
where TotalCount > 1