使用Mouse在Java中设置弧位置

Question

我正在写一个2D程序。在paintComponent我创建了一个弧。

public class Board extends Panel{

    protected void paintComponent(Graphics g){
        super.paintComponent(g);
        Graphics2D graphics2d = (Graphics2D)g;
        int x = MouseInfo.getPointerInfo().getLocation().x;//set mouses current position
        int y = MouseInfo.getPointerInfo().getLocation().y;

        graphics2d.setStroke(wideStroke);
        graphics2d.draw(new Arc2D.Double(200, 200, 100, 100, ?, 180, Arc2D.OPEN));

    }
}

在我的主要内容中，我使用Thread来更新图表。 ?的位置是起始角度。每当我改变这个时，弧就会像一个车轮一样移动一圈。是否有可能让弧线运动跟随鼠标？例如? = 270

我将如何做到这一点？ （对不起我糟糕的油漆技巧！）

Answer 1

所以基于Java 2d rotation in direction mouse point

的信息

我们需要两件事。我们需要锚点（它将是弧的中心点）和目标点，这将是鼠标点。

使用MouseMotionListener，可以监控组件中的鼠标移动

// Reference to the last known position of the mouse...
private Point mousePoint;
//....
addMouseMotionListener(new MouseAdapter() {
    @Override
    public void mouseMoved(MouseEvent e) {
        mousePoint = e.getPoint();                    
        repaint();                    
    }                
});

接下来我们需要计算这两点之间的角度......

if (mousePoint != null) {
    // This represents the anchor point, in this case, 
    // the centre of the component...
    int x = width / 2;
    int y = height / 2;

    // This is the difference between the anchor point
    // and the mouse.  Its important that this is done
    // within the local coordinate space of the component,
    // this means either the MouseMotionListener needs to
    // be registered to the component itself (preferably)
    // or the mouse coordinates need to be converted into
    // local coordinate space
    int deltaX = mousePoint.x - x;
    int deltaY = mousePoint.y - y;

    // Calculate the angle...
    // This is our "0" or start angle..
    rotation = -Math.atan2(deltaX, deltaY);
    rotation = Math.toDegrees(rotation) + 180;
}

从这里开始，您需要减去90度，这将使您的弧开始角度，然后使用180度的范围。