如果当前日期在Oracle SQL的2个日期之间,我想选择1
。
我在阅读完其他问题后写了一篇SQL。
https://stackoverflow.com/questions/2369222/oracle-date-between-query
但它只返回null。 sysdate
是日期格式为01/05/2014
的当前日期DD/MM/YYYY
。
我写的SQL是:
select 1 from dual
WHERE to_date(sysdate,'DD/MM/YYYY')
BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY')
AND TO_DATE('20/06/2014', 'DD/MM/YYYY');
和
select 1 from dual
WHERE to_date(sysdate,'DD/MM/YYYY') >= TO_DATE('28/02/2014', 'DD/MM/YYYY')
AND to_date(sysdate,'DD/MM/YYYY') < TO_DATE('20/06/2014', 'DD/MM/YYYY');
答案 0 :(得分:59)
您无需将to_date()
应用于sysdate
。它已经存在了:
select 1
from dual
WHERE sysdate BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY') AND TO_DATE('20/06/2014', 'DD/MM/YYYY');
如果您担心日期中的时间组件,请使用trunc()
:
select 1
from dual
WHERE trunc(sysdate) BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY') AND
TO_DATE('20/06/2014', 'DD/MM/YYYY');
答案 1 :(得分:0)
SELECT to_char(emp_login_date,'DD-MON-YYYY HH24:MI:SS'),A.*
FROM emp_log A
WHERE emp_login_date BETWEEN to_date(to_char('21-MAY-2015 11:50:14'),'DD-MON-YYYY HH24:MI:SS')
AND
to_date(to_char('22-MAY-2015 17:56:52'),'DD-MON-YYYY HH24:MI:SS')
ORDER BY emp_login_date
答案 2 :(得分:0)
select
distinct
e1.enddate,
e3.startdate,
DATEDIFF(DAY,e1.enddate,e3.startdate)-1 as [Datediff]
from #temp e1
join #temp e3 on e1.enddate < e3.startdate
/* Finds the next start Time */
and e3.startdate = (select min(startdate) from #temp e5
where e5.startdate > e1.enddate)
and not exists (select * /* Eliminates e1 rows if it is overlapped */
from #temp e5
where e5.startdate < e1.enddate and e5.enddate > e1.enddate);