Question

我有一个下拉列表，我绑定了一个List，如：

var ddlLst2 = new List<string> { "Audi", "BMW", "Ford", "Vauxhall"};
ddlLst2.Sort();

foreach (var item in ddlLst2)
{
    DropDownList2.Items.Add(new ListItem(item));

}

结果：

<select id="DropDownList2" onchange="javascript:setTimeout('__doPostBack(\'DropDownList2\',\'\')', 0)" name="DropDownList2">

    <option value="--Please Select--" selected="selected"></option>
    <option value="Audi"></option>
    <option value="BMW"></option>
    <option value="Ford"></option>
    <option value="Vauxhall"></option>

</select>

但我想在每个项目中添加一个属性，预期结果如下：

预期结果：

<select id="DropDownList2" onchange="javascript:setTimeout('__doPostBack(\'DropDownList2\',\'\')', 0)" name="DropDownList2">

    <option value="--Please Select--" selected="selected"></option>
    <option value="Audi" code="1"></option>
    <option value="BMW" code="2"></option>
    <option value="Ford" code="3"></option>
    <option value="Vauxhall" code="4"></option>

</select>

正如您在上面看到的，添加了一个额外的属性"code"，code的值来自查询。

Answer 1

foreach (var item in ddlLst2)
            {
                ListItem tmp = new ListItem();
                tmp.Text = item.ToString();
                tmp.Attributes.Add("AttribName", "AttribValue");
                DropDownList2.Items.Add(tmp);

            }

或类似的东西......玩弄tmp的可用属性......

Answer 2

void Main()
{
var ddlLst2 = new List<string> { "Audi", "BMW", "Ford", "Vauxhall"};
        ddlLst2.Sort();

        var ctrls = new List<ListItem>();
        int i =0;
        foreach (var item in ddlLst2)
        {
            //DropDownList2.Items.Add(new ListItem(item));
            ListItem li = new ListItem(item);
            li.Attributes.Add("code", i.ToString());
            ctrls.Add(li);
            i++;
        }

        foreach (ListItem element in ctrls)
        {
            Console.WriteLine(element.Attributes["code"]);
        }
}

Answer 3

对于JS事件：您可以从您的javascript订阅它。即使用JQuery： $('#DropDownList2').change(function() { alert("Fired!"); });

Answer 4

protected void dropdownlist_DataBound(object sender, EventArgs e)
    {
        DataTable dt = new DataTable();
        DataView dv = (DataView)sqldatasource.Select(DataSourceSelectArguments.Empty);
        dt = dv.ToTable();

        foreach (DataRow dr in dt.Rows)
        {
            dropdownlist.Items.FindByValue(dr[0].ToString()).Attributes.Add("attr0", dr[2].ToString());
            dropdownlist.Items.FindByValue(dr[0].ToString()).Attributes.Add("attr1", dr[3].ToString());
            dropdownlist.Items.FindByValue(dr[0].ToString()).Attributes.Add("attr2", dr[4].ToString());

        }

    }

如何在c＃中的DropDown列表中添加额外的属性

4 个答案: