Question

我使用此方法从HICON获取BufferedImage

public BufferedImage getIcon(Pointer hIcon) {
    int   width =16;
    int   height=16;
    short depth =24;
    BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB);

    byte[] lpBitsColor = new byte[width*height*depth/8];
    byte[] lpBitsMask  = new byte[width*height*depth/8];
    BITMAPINFO info     = new BITMAPINFO();
    BITMAPINFOHEADER hdr= new BITMAPINFOHEADER();
    info.bmiHeader   =hdr;
    hdr.biWidth      =width;
    hdr.biHeight     =height;
    hdr.biPlanes     =1;
    hdr.biBitCount   =depth;
    hdr.biCompression=BI_RGB;

    Pointer hDC =u32.GetDC(null);
    ICONINFO piconinfo = new ICONINFO();
    u32.GetIconInfo(hIcon, piconinfo);
    gdi32.GetDIBits(hDC, piconinfo.hbmColor, 0, height, lpBitsColor, info, DIB_RGB_COLORS);
    gdi32.GetDIBits(hDC, piconinfo.hbmMask , 0, height, lpBitsMask , info, DIB_RGB_COLORS);

    int r, g, b, a, argb;
    int x=0, y=height-1;
    for (int i = 0; i < lpBitsColor.length; i=i+3) {
        b =      lpBitsColor[i  ] & 0xFF;
        g =      lpBitsColor[i+1] & 0xFF;
        r =      lpBitsColor[i+2] & 0xFF;
        a = 0xFF-lpBitsMask [i  ] & 0xFF;
        //System.out.println(lpBitsMask[i]+" "+lpBitsMask[i+1]+" "+lpBitsMask[i+2]);
        argb= (a<<24) | (r<<16) | (g<<8) | b;       
        image.setRGB(x, y, argb);
        x=(x+1)%width;
        if (x==0) y--;
    }

    u32.ReleaseDC(null, hDC);

    return image;
}

当我将构建路径更改为32位jre时，该方法就像魅力一样工作，但是当构建路径是64位jre并尝试调试它时，JVM在此行上发生访问冲突时崩溃：

gdi32.GetDIBits(hDC, piconinfo.hbmColor, 0, height, lpBitsColor, info, DIB_RGB_COLORS);

预览本机调用工作正常，但在尝试访问gdi32.dll（在其64位版本（位于system32上））时，此方法崩溃了。

即时运行Windows 7 64位机器

由于

HICON到BufferedImage会使jvm在64位上崩溃

0 个答案: