Question

我有这个XML

<?xml version="1.0" encoding="UTF-8"?>
<document>
<metadata>
  <field name="MyWebsite/Metadata/Keywords">marketing business</field>
  <field name="MyWebsite/Metadata/PageTitle">PageTitle1</field>
  <field name="MyWebsite/Metadata/active_url">marketing business link</field>
</metadata>
<metadata>
  <field name="MyWebsite/Metadata/Keywords">planning development</field>
 <field name="MyWebsite/Metadata/PageTitle">PageTitle2</field>
 <field name="MyWebsite/Metadata/active_url">planning development link</field>
</metadata>
<metadata>
  <field name="MyWebsite/Metadata/Keywords">learning development</field>
  <field name="MyWebsite/Metadata/PageTitle">PageTitle3</field>
  <field name="MyWebsite/Metadata/active_url">learning development link</field>
</metadata>

我的XSL代码是

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
 <html>
 <body>
 <h2>Updated Tool Information:</h2>
 <table border="1">
   <xsl:for-each select="document/metadata/field">
   <tr>
   <xsl:if test = "@name = 'MyWebsite/Metadata/Keywords' and contains(.,'development')">
      <td>Page Title: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/PageTitle']"/></td>
      <td>URL: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/active_url']"/>    </td>
   </xsl:if>      
   </tr>
   </xsl:for-each>
  </table>
  </body>
  </html>
</xsl:template>

我的目标是将字符串与'development'匹配，该页面将仅显示Page title和URL。

我的预期结果应该显示如下 -

页面标题：PageTitle2 URL：规划开发链接
页面标题：PageTitle3网址：学习发展链接

不幸的是，上面的代码没有显示任何内容，它是空白的。

Answer 1

而不是

   <xsl:for-each select="document/metadata/field">
   <tr>
   <xsl:if test = "@name = 'MyWebsite/Metadata/Keywords' and contains(.,'development')">
      <td>Page Title: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/PageTitle']"/></td>
      <td>URL: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/active_url']"/>    </td>
   </xsl:if>      
   </tr>
   </xsl:for-each>

你想要

   <xsl:for-each select="document/metadata[field[@name = 'MyWebsite/Metadata/Keywords' and contains(.,'development')]]">
   <tr>

      <td>Page Title: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/PageTitle']"/></td>
      <td>URL: <xsl:value-of select="field[@name = 'MyWebsiteMetadata/active_url']"/>    </td>

   </tr>
   </xsl:for-each>

XSL元素匹配条件并仅显示特定的xml节点元素

1 个答案: