Question

我想删除表格中的所有数据，并使用比例如2天更长的邮票。我创建了以下查询：

DELETE FROM temporary_data WHERE stamp < CURDATE() - INTERVAL 1 DAY;

但这似乎不起作用。我的邮票看起来像这样：2014-04-29 15:37:00

我认为CURDATE（）只返回2014-04-30，这与邮票不匹配。谁能帮帮我？

Answer 1

从现在开始的2天以上可以删除

DELETE FROM temporary_data WHERE stamp <  date_sub(now(),INTERVAL 2 day)

这里如何在mysql中看起来像

mysql> select now(),date_sub(now(),INTERVAL 2 day) ;
+---------------------+--------------------------------+
| now()               | date_sub(now(),INTERVAL 2 day) |
+---------------------+--------------------------------+
| 2014-04-30 12:54:39 | 2014-04-28 12:54:39            |
+---------------------+--------------------------------+

没有H:i:s，它应该是

mysql> select CURDATE(),date(date_sub(now(),INTERVAL 2 day)) ;
+------------+--------------------------------------+
| CURDATE()  | date(date_sub(now(),INTERVAL 2 day)) |
+------------+--------------------------------------+
| 2014-04-30 | 2014-04-28                           |
+------------+--------------------------------------+

Answer 2

始终在删除前选择

SELECT from temporary_data
where stamp between date_sub(now(),INTERVAL 2 DAY) and now();

删除查询

delete from temporary_data
where stamp between date_sub(now(),INTERVAL 2 DAY) and now();

您可以根据您的要求修改时间间隔，以获得更多阅读http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

删除基于戳mySQL的旧数据

2 个答案: