Question

我在做一个问题，我需要知道用户是否足够大或不喝酒。用户输入他们的生日，他们必须在1993年2月或之前出生才合法。这是我到目前为止所得到的。

#User inputs their birthday. 
year = int(input("Enter your birth year(as a number): "))
month = int(input("Enter your birth month(as a number): "))

#Finding out if they are old enough to drink or not
found=False
if (year<=1993):
    found ==True
    print("You are old enough to drink in Washington")
elif (month<=2):
    found ==True
    print("You are old enough to drink in Washington")
elif (month>=3):
    found ==True
    print("You aren't 21 yet")

当我输入1993年时，3。它会说你已经够大了，不应该喝酒。

Answer 1

你应该追溯你的陈述的逻辑。

我可能会尝试这样做：

found=False
if year < 1993:   # If less than 93, then month doesn't matter
    found = True
elif (year == 1993) and (month <= 4):   # If 1993, check month
    found = True

if found:
    print("You are old enough to drink in Washington")
else:
    print("You aren't 21 yet")

您可能会考虑使用date模块来获取年份和月份，而不是修复该值，以便每个月都有人编辑和更新该程序。

Answer 2

您将希望使用更多如下所示的代码。您所拥有的月份测试是一个问题，因为它并不是所有测试年份。你的代码最后也不需要elif，因为它只是一个别的。

found=False
if year<1993 or (year==1993 and month<=2):
    found =True
    print("You are old enough to drink in Washington")
else:
    found =True
    print("You aren't 21 yet")

Answer 3

Hmmmm。这是两行代码..

found = (year<1993 or (year==1993 and month<=2)) and True or False
print "You are old enough to drink in Washington" if found else "You aren't 21 yet".

如何在python中使用if语句输出字符串语句

3 个答案: