使用jquery更改文本和类

时间:2014-04-30 01:29:07

标签: javascript jquery

我整天都被困在一个正在研究的项目上。所有的功能都存在,我只是遇到了jquery的麻烦,有人可以帮助我吗?

这里是应用程序的视觉效果:

http://imgur.com/nsdgubB

非常简单,当我点击“喜欢帖子”时,通过ajax调用一个函数来运行对数据库计数的更新,当我按“Dislike”时也是如此

我的问题在于JQuery,我似乎无法弄明白如何制作它,所以当点击“Like post”时,它会变成“已经喜欢”而“已经不喜欢”变成“不喜欢”

CSS类:

    "Like Post" = fa fa-thumbs-up like_btn
    "Dislike Post" = fa fa-thumbs-down dislike_btn
    "Already Liked" = fa fa-check like_btn
    "Already Disliked" = fa fa-check fa-check-dislike dislike_btn"

这是当前的JQuery,我尝试了一些不同的东西,但似乎没有任何工作,我非常感谢任何建议。

$('.fa-thumbs-up').click(function() {

var annid = $(this).attr('id');
update_likes(annid, 'like');
//code goes here
});

$('.fa-thumbs-down').click(function() {

var annid = $(this).attr('id');
update_likes(annid, 'dislike');
//code goes here
});

更新的JFIDDLE:http://jsfiddle.net/T9wvL/2/

2 个答案:

答案 0 :(得分:1)

切换元素比交换文本更容易,所以我稍微修改了HTML。

http://jsfiddle.net/isherwood/T9wvL/8

.hide {
    display: none;
}

<article>
    <div class="updates updates-like">
        <i class="fa fa-thumbs-up like_btn" id="like"> 
            <span>Like Post</span>
            <span class="hide">Already liked</span>
        </i> 
    </div>

    <div class="updates updates-dislike">
        <i class="fa fa-thumbs-down dislike_btn" id="dislike">
            <span>No Good</span>
            <span class="hide">Already disliked</span>
        </i>
    </div>
</article>

$('.updates').click(function () {
    $(this).find('i').toggleClass('fa-thumbs-up fa-thumbs-down')
        .find('span').toggleClass('hide');
});

答案 1 :(得分:0)

<强> HTML:

<article>
    <div class="updates-like">
        <i class="fa fa-thumbs-up like_btn" id="<? echo $update->annid; ?>">
            <span>Like Post </span>
        </i> 
    </div>
    <div class="updates-dislike">
        <i class="fa fa-thumbs-down dislike_btn" id="<?echo $update->annid;?>">
            <span>No Good</span>
        </i> 
    </div>
</article>

<强> JQuery的:

$('.like_btn').click(function () {
    /*This here runs the update function on the DB.. Not Important
       var annid = $(this).attr('id');
       update_likes(annid, 'like');*/

        //Code here to change "Like Post" to "already Liked" ON CLICK, and to change "already disliked" back to "No Good"

    if ( $(this).hasClass('fa-thumbs-up') ) {
        $(this).removeClass('fa-thumbs-up')
               .addClass('fa-check')
               .find('span')
               .text('Already Liked');
        if ( $('.dislike_btn').hasClass('fa-check fa-check-dislike') ) {
            $('.dislike_btn').removeClass('fa-check fa-check-dislike')
                             .addClass('fa-thumbs-down')
                             .find('span')
                             .text('No Good');
        }
    }

    return true;

});

$('.dislike_btn').click(function () {
    /*This here runs the update function on the DB.. Not Important
        var annid = $(this).attr('id');
        update_likes(annid, 'dislike'); */

        //Code here to change "No Good" to "already disliked" ON CLICK, and to change "already Liked" back to "No Like Post"

    if ( $(this).hasClass('fa-thumbs-down') ) {
        $(this).removeClass('fa-thumbs-down')
               .addClass('fa-check fa-check-dislike')
               .find('span')
               .text('Already Disliked');
        if ( $('.like_btn').hasClass('fa-check') ) {
            $('.like_btn').removeClass('fa-check')
                          .addClass('fa-thumbs-up')
                          .find('span')
                          .text('Like Post');
        }
    }

    return true;

});

JSFiddle 应该适用于您需要的内容。我试图优化你的代码,但我希望它仍能正常工作。