Question

我有一些需要多次调用的函数，因此

int i;
i = 10;
while (i > 0)
{
    selectletter(wordArray);
    computerTurn(wordArray);
    printGrid(grid);
    i--;
}

函数选择工作正常，并且在该函数的末尾附近，它调用另一个函数“claimword”。 Claimword运行完全正常，但在函数结束时，程序在上下文用完时崩溃，而不是像上面所示那样转移到计算机上。我抬头看着如何“退出”一个功能，每个人都说“返回”。即使在虚函数中也能正常工作。但是，当我尝试使用return时，除了return语句被忽略之外的任何内容之外什么也没发生。谁能告诉我为什么return语句不起作用？

void claimword(Tile grid[7][6], char letter, string wordArray[100])
{
    cout << "Would you like to claim a word? (Y/N)" << endl;
    char chooseinput;
    cin >> chooseinput;
    if ((chooseinput == 'y') || (chooseinput == 'Y'))
    {
    printGrid(grid);
    cout << "Please enter the word you would like to claim." << endl;
    string input;
    cin >> input;
    int inthegrid = 0;
    int errormessage = 0;
    compchecker(grid, input, inthegrid);
    int length;
    if (inthegrid = 1)
    {
        for(int i = 0; i < 100; ++i)
        {
            if (input == wordArray[i])
            {
                if (input.find(letter) != std::string::npos)
                {
                    string strl;
                    strl = wordArray[i];

                    length = strl.length();
                    cout << "You have claimed the word " << strl << endl;
                    wordArray[i] = "/";

                }
                else
                {
                    errormessage = 1;
                }

            }
            else
            {
                ///cout << "Sorry, that word is not in the dictionary." << endl;
                errormessage = 2;
            }
        }
        if (errormessage = 1)
        {
            cout << "Sorry you cannot claim that word." << endl;
        }
        if (errormessage = 2)
        {
            cout << "Sorry, that word is not in the dictionary." << endl;

        }
                    if (length == 3)
                    {
                        human.humanpoints = human.humanpoints + 1;
                        wordsthisturn = wordsthisturn + 1;
                        cout << "You have earned one point!" << endl;
                    }
                    if (length == 4)
                    {
                        human.humanpoints = human.humanpoints + 2;
                        wordsthisturn = wordsthisturn + 2;
                        cout << "You have earned two points!" << endl;
                    }
                    if (length == 5)
                    {
                        human.humanpoints = human.humanpoints + 4;
                        wordsthisturn = wordsthisturn + 4;
                        cout << "You have earned four points!" << endl;
                    }
                    if (length == 6)
                    {
                        human.humanpoints = human.humanpoints + 8;
                        wordsthisturn = wordsthisturn + 8;
                        cout << "You have earned eight points!" << endl;
                    }
                    if (length == 7)
                    {
                        human.humanpoints = human.humanpoints + 16;
                        wordsthisturn = wordsthisturn + 16;
                        cout << "You have earned sixteen points!" << endl;
                    }
                    else
                    {
                        cout << "Your word was too small to claim any points." << endl;
                    }

    }
    }
    else
    {
        cout << "End of Player Turn." << endl;
        //return;
    }
    cout <<"Test1";
    return;
    cout <<"Test2";

}

无论我给它的输入（y / n等），“Test1”显示，但“Test2”不显示。我的理论是程序不会一直返回，或者我只是没有正确使用它。

编辑：

在主函数中使用已编辑的语句

        selectletter(wordArray);
        cout << "test11";
        computerTurn(wordArray);

应该发生的是应该调用selectletter函数。在其末尾的selectletter函数调用另一个函数，claimWord。 claimWord上面发布。在函数结束时，它应该结束。应该没有什么可以做的，并且在所有关于点的if / elses之后，即使没有得分，或者函数中的任何事情发生，该函数应该结束。然后程序应显示“test11”，但不会显示。

EDIT2：

void selectletter(string wordArray[100])
{
    cout << endl;
    cout << "REMAINING LETTERS:" << endl;
    cout << human.humanletters << endl;
    cout << "Select a letter.";
    int length;
    length = human.humanletters.size();
    char input;
    cin >> input;
    int column;
    int row = 7;
    int cinput;
    //mght have to change since 0 is the first val
    cout << "What column would you like to drop that in? (1-7)";
    cin >> cinput;
    column = cinput - 1;
    //cout << "Test1";
    while (row > 0)
    {
    if (grid[row-1][column].active == true)
    {
        row--;
        //cout << "Test3";
    }
    else
        for(int i = 0; i < length; i++)
        {

        if(human.humanletters[i] == input)
        {
            //cout << "Test5";
            human.humanletters.erase(std::remove(human.humanletters.begin(), human.humanletters.end(), input), human.humanletters.end());
            grid[row-1][column].letter = input;
            grid[row-1][column].active = true;
            cout << endl;
            //cout << "Test6";
            claimword(grid, input, wordArray);
            //this removes ALL instances of the letter, however
        }
        break;
        //need to add something for if the letter is not in the string
    //}
        //row = 9999;
    }
}
}

Answer 1

无论我给它的输入（y / n等），“Test1”显示，但“Test2”不显示。

这就是应该做的事情。您在显示return之后和显示Test1之前致电Test2，因此跳过后者。 return是立即返回调用当前函数的函数。

Answer 2

您的while循环的条件为while (row > 0)，而row时只会递减(grid[row-1][column].active == true)。如果评估为false，则不会减少row并且您的程序将永远运行。

也许你的break;意味着打破了while循环，但它所做的只是打破for循环。 break语句突破最近的封闭循环/切换块。

“返回”不起作用，不能“退出”一个功能

2 个答案: