Question

我正在尝试将datetimepicker设置为今天的日期和选定的日期。然后将第二个选择器设置为明天日期和选定时间。我的问题是，虽然我称这种方法，但它不会增加日子。如何更改此项以添加一天并保持所需的时间？

如果我删除转换我得到一个错误：System.DateTime.DateTime(int, int, int, int, int, int)的最佳重载方法匹配有一些无效的参数

RadDateTimePicker1.SelectedDate = new DateTime(DateTime.Now.Year, DateTime.Now.Month, DateTime.Now.Day, 17, 30, 0);
RadDateTimePicker2.SelectedDate = new DateTime(DateTime.Now.Year, DateTime.Now.Month, Convert.ToInt32(DateTime.Now.AddDays(1)), 5, 30, 0);

Answer 1

我想你想要DateTime.Now.AddDays(1).Day

new DateTime(DateTime.Now.Year, DateTime.Now.Month, DateTime.Now.AddDays(1).Day, 5, 30, 0);

AddDays方法返回新的DateTime，您无法将其转换为int。只需使用Day属性即可获取新日期时间。

更新： @UlugbekUmirov关于他的评论是正确的，为了解决这个问题，你可以尝试：

var now = DateTime.Now;
DateTime first = new DateTime(now.Year,now.Month,now.Day, 17, 30, 0);
DateTime second;
if (now.Day == DateTime.DaysInMonth(now.Year, now.Month))
{
     if(DateTime.Now.Month == 12)
           second = new DateTime(now.Year+1, 1, 1, 5, 30, 0);
      else
           second = new DateTime(now.Year, now.Month+1, 1, 5, 30, 0);
}
else
{
    second = new DateTime(now.Year, now.Month, now.Day+1, 5, 30, 0);
}
RadDateTimePicker1.SelectedDate = first;
RadDateTimePicker2.SelectedDate = second;

Answer 2

尝试类似

的内容

DateTime today    = DateTime.Now.Date + new TimeSpan( 0 , 17 , 30 , 0 ) ;
DateTime tomorrow = today.Date        + new TimeSpan( 1 ,  5 , 30 , 0 ) ;

RadDateTimePicker1.SelectedDate = today    ;
RadDateTimePicker2.SelectedDate = tomorrow ;

Answer 3

DateTime.Now可以在通话之间切换，最好执行以下操作：

DateTime today = DateTime.Today;
RadDateTimePicker1.SelectedDate = today.Add(new TimeSpan(17, 30, 0));
RadDateTimePicker2.SelectedDate = today.Add(new TimeSpan(1, 5, 30, 0));

Answer 4

接受的答案非常详细（问题中的示例代码也是如此）。

为什么不这样：

RadDateTimePicker1.SelectedDate = DateTime.Today.AddHours(17.5);
RadDateTimePicker2.SelectedDate = DateTime.Today.AddHours(29.5);

或者，如果你想更清楚第二行的时间成分，你可以改用它：

RadDateTimePicker2.SelectedDate = DateTime.Today.AddDays(1).AddHours(5.5);

从'DateTime'到'Int32'的无效演员表

4 个答案: