每当我在一个单元格上向左滑动时,我的应用程序崩溃,这就是我得到的
-[UITableViewCellScrollView _tableView]: unrecognized selector sent to instance 0x166a1960
-[UITableViewCellScrollView _tableView]: unrecognized selector sent to instance 0x166a1960
Stack Trace: (
0 CoreFoundation 0x2fc08f23 <redacted> + 154
1 libobjc.A.dylib 0x3a39fce7 objc_exception_throw + 38
2 CoreFoundation 0x2fc0c837 <redacted> + 202
3 CoreFoundation 0x2fc0b137 <redacted> + 706
4 CoreFoundation 0x2fb5a098 _CF_forwarding_prep_0 + 24
5 UIKit 0x3262ef91 <redacted> + 184
6 UIKit 0x325be3f5 <redacted> + 816
7 UIKit 0x32468a21 <redacted> + 148
8 UIKit 0x325ce0cf <redacted> + 78
9 UIKit 0x324681eb <redacted> + 458
10 UIKit 0x32467c4b <redacted> + 666
11 UIKit 0x3243ce75 <redacted> + 196
12 UIKit 0x3243b541 <redacted> + 7120
13 CoreFoundation 0x2fbd3fef <redacted> + 14
14 CoreFoundation 0x2fbd34b7 <redacted> + 206
15 CoreFoundation 0x2fbd1ca7 <redacted> + 630
16 CoreFoundation 0x2fb3c769 CFRunLoopRunSpecific + 524
17 CoreFoundation 0x2fb3c54b CFRunLoopRunInMode + 106
18 GraphicsServices 0x34aa96d3 GSEventRunModal + 138
19 UIKit 0x3249b891 UIApplicationMain + 1136
20 Event Receiver 0x000c3849 main + 116
21 libdyld.dylib 0x3a89dab7 <redacted> + 2
)
我试图为 - [NSObject(NSObject)doesNotRecognizeSelector:]添加符号断点但是没有显示哪个代码发送了那个选择器
更新:这次我使用了模拟器,并试图让应用程序崩溃,我现在得到了这个:
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UITableViewCellScrollView _tableView]: unrecognized selector sent to instance 0x8e46570'
*** First throw call stack:
(
0 CoreFoundation 0x01ad91e4 __exceptionPreprocess + 180
1 libobjc.A.dylib 0x018588e5 objc_exception_throw + 44
2 CoreFoundation 0x01b76243 -[NSObject(NSObject) doesNotRecognizeSelector:] + 275
3 CoreFoundation 0x01ac950b ___forwarding___ + 1019
4 CoreFoundation 0x01ac90ee _CF_forwarding_prep_0 + 14
5 UIKit 0x00785f7a -[UITableViewCellScrollView gestureRecognizerShouldBegin:] + 203
6 UIKit 0x008b5466 -[UIGestureRecognizer _shouldBegin] + 1309
7 UIKit 0x008b1d89 -[UIGestureRecognizer setState:] + 171
8 UIKit 0x008e39d7 -[UIPanGestureRecognizer touchesMoved:withEvent:] + 142
9 UIKit 0x0099792a -[UIScrollViewPanGestureRecognizer touchesMoved:withEvent:] + 89
10 UIKit 0x005597d8 -[UIWindow _sendGesturesForEvent:] + 649
11 UIKit 0x0055a971 -[UIWindow sendEvent:] + 1021
12 UIKit 0x0052c5f2 -[UIApplication sendEvent:] + 242
13 UIKit 0x00516353 _UIApplicationHandleEventQueue + 11455
14 CoreFoundation 0x01a6277f __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 15
15 CoreFoundation 0x01a6210b __CFRunLoopDoSources0 + 235
16 CoreFoundation 0x01a7f1ae __CFRunLoopRun + 910
17 CoreFoundation 0x01a7e9d3 CFRunLoopRunSpecific + 467
18 CoreFoundation 0x01a7e7eb CFRunLoopRunInMode + 123
19 GraphicsServices 0x03dba5ee GSEventRunModal + 192
20 GraphicsServices 0x03dba42b GSEventRun + 104
21 UIKit 0x00518f9b UIApplicationMain + 1225
22 Event Receiver 0x000056cd main + 141
23 libdyld.dylib 0x026a5701 start + 1
)
答案 0 :(得分:1)
通过对单元格应用一些着色,我看到当我从附件视图中滑动单元格时崩溃
解决方法是在tableView中将accessoryType设置为UITableViewCellAccessoryNone:cellForRowAtIndexPath:
cell.accessoryType = UITableViewCellAccessoryNone;
<强>参考文献:强> - 如何使用动作制作可滑动的表格视图单元格 - 不使用滚动视图的坚果here
- 仔细查看表视图单元格here
答案 1 :(得分:1)
嘿〜我刚刚在我的自定义UItableview Cell中删除了以下代码,但我不知道它是否可以帮到你
self.contentView.userInteractionEnabled = NO;
在我的情况下,当我尝试在iOS7中的自定义userinteractionEnabled
中向左或向右滑动时,禁用单元格内容视图的UItableView
会导致完全相同的崩溃,
它应该通过删除来修复
答案 2 :(得分:0)
考虑到你所得到的错误以及这些问题:
0x01ac90ee _CF_forwarding_prep_0 + 14
0x00785f7a -[UITableViewCellScrollView gestureRecognizerShouldBegin:] + 203
似乎您以某种方式将UITableViewCellScrollView
的实例设置为手势识别器的代理。由于UITableViewCellScrollView
可能没有实现UIGestureRecognizerDelegate
协议,因此最终会出现无法识别的选择器异常。
仔细检查每个表格单元格中的手势识别器,并检查其代表的身份。