如何用％2B替换+：
这是我的代码
x<-"asflj + ldjjsf ljsdlafj"
gsub("+","%2B", x)
我的输出是：
"%2Ba%2Bs%2Bf%2Bl%2Bj%2B %2B+%2B %2Bl%2Bd%2Bj%2Bj%2Bs%2Bf%2B %2Bl%2Bj%2Bs%2Bd%2Bl%2Ba%2Bf%2Bj%2B"
我希望它是"asflj %20 ldjjsf ljsdlafj"
答案 0 :(得分：3)
+ is a metacharacter然后您可以设置fixed=TRUE跳过它并获得您需要的内容。
> gsub("+","%2B", x, fixed=TRUE)
[1] "asflj %2B ldjjsf ljsdlafj"
或使用\\+
> gsub("\\+","%2B", x)
[1] "asflj %2B ldjjsf ljsdlafj"