如何使用mysql like子句缩小范围

Question

我运行命令select * from victims where fname like '%a%' or address like '%194%';，我得到了这个

+----+---------+---------+---------+--------+--------------------+--------------------+------+
| id | fname   | mname   | lname   | gender | address            | email      | card |
+----+---------+---------+---------+--------+--------------------+--------------------+------+
|  1 | Ryan    | Anthony | O'Keefe | M      | 194 lou Lane | ryan@songoda.com   | 2543 |
|  3 | Beau    | Jacob   | Diddly  | M      | 21 fake cr         | elmo@q.com      | 6264 |
|  4 | Anthony | Quinn   | Jims    | M      | 34 lol lane        | chicks@hotmail.com | 3456 |
+----+---------+---------+---------+--------+--------------------+--------------------+------+

对于那个结果我只希望显示数字1，因为这是唯一同时包含名字中的a和地址中的194的人。有人可以指出我做错了吗？

Answer 1

select * from victims where fname like '%a%' or address like '%194%';

应该是

select * from victims where fname like '%a%' AND address like '%194%';

如果您希望名字以A

开头，您也可以从前面取模数

select * from victims where fname like 'a%' AND address like '194%';