如何在C＃中按下并移动鼠标？

Question

我需要在C＃中发送鼠标信号，以便其他应用程序注册它们。确切地说，我需要模拟鼠标按钮和鼠标的移动。有没有办法在C＃中做到这一点？ （Windows）中

Answer 1

mouse's cursor position是一个可设置的属性 - 您可以使用它在任何地方移动鼠标。

Answer 2

您需要调用SendInput API函数。

请参阅here了解P / Invoke定义。

Answer 3

就按钮而言，您可以执行以下操作

[DllImport("user32.dll")]
    public static extern uint SendInput(uint nInputs, ref Input pInputs, int cbSize);

    const uint MOUSEEVENTF_LEFTDOWN = 0x0002;
    const uint MOUSEEVENTF_LEFTUP = 0x0004;
    const uint MOUSEEVENTF_RIGHTDOWN = 0x0008;
    const uint MOUSEEVENTF_RIGHTUP = 0x0010;

    public static void DoMouseClick()
    {
        var input =
            new Input
                {
                    type = 0,
                    mouseinput =
                        new Mouseinput
                            {
                                dx = Cursor.Position.X,
                                dy = Cursor.Position.Y,
                                dwFlags = MOUSEEVENTF_LEFTDOWN
                            }
                };


        SendInput(1, ref input, 28);
    }

    [StructLayout(LayoutKind.Explicit, Size = 28)]
    public struct Input
    {
        [FieldOffset(0)]
        public uint type;
        [FieldOffset(4)]
        public Mouseinput mouseinput;
    };
    [StructLayout(LayoutKind.Explicit, Size = 28)]
    public struct Mouseinput
    {
        [FieldOffset(0)]
        public int dx;
        [FieldOffset(4)]
        public int dy;
        [FieldOffset(8)]
        public uint mouseData;
        [FieldOffset(12)]
        public uint dwFlags;
        [FieldOffset(16)]
        public uint time;
        [FieldOffset(20)]
        public uint dwExtraInfo;
    }