Question

我正在创建一个游戏，用户必须猜出单词中的字母，如果他们猜错了，如果他们猜错了就会显示单词中的字母，它会减去生命。问题是，如果他们猜对了，就打印出英菲尼迪这个词。这是我的代码：

char words[] = new char[getRandomPirateWord().length()];
     char words2[] = new char[getRandomPirateWord().length()];
     for(int i = 0; i < getRandomPirateWord().length(); i++)
     {
         words[i] = getRandomPirateWord().charAt(i);
         words2[i] = (getRandomPirateWord().charAt(i)==' ')?' ':'*';
     }
     while(getGuessLeft()>0)
     {
         getLettersGuesed().add(letter);

         if (!randomPirateWord.contains(letter+""))
         {
         setGuessLeft(getGuessLeft() - 1);
         System.out.println("You lost a life, now have " + getGuessLeft());
         }

         for(int i1 = 0; i1 <getRandomPirateWord().length(); i1++)
         {
            if(words[i1] == letter)
            {
                  words2[i1] = letter;
            }
        }

        for(int i1 = 0; i1 < getRandomPirateWord().length(); i1++)
        {
            System.out.print(words2[i1]);

Answer 1

问题似乎是while循环永远不会终止。这取决于如果您猜测单词内的字母，则while循环开始，因为您永远不会更改变量字母的值

while(getGuessLeft()>0) {
    getLettersGuesed().add(letter);
    if (!randomPirateWord.contains(letter+"")) {
        setGuessLeft(getGuessLeft() - 1);
        System.out.println("You lost a life, now have " + getGuessLeft());
    }
    for(int i1 = 0; i1 <getRandomPirateWord().length(); i1++) {
        if(words[i1] == letter) words2[i1] = letter;
    }
    for(int i1 = 0; i1 < getRandomPirateWord().length(); i1++){
        System.out.print(words2[i1]);
    }
}

代码循环无限

1 个答案: